"Latin" meaning in Anglais

See Latin in All languages combined, or Wiktionary

Adjective

IPA: \ˈlæt.n̩\, \ˈlæt.ɪn\, ˈlæt.n̩ Audio: En-us-Latin.ogg , LL-Q1860 (eng)-Grendelkhan-Latin.wav
  1. Latin, relatif à la langue latine.
    Sense id: fr-Latin-en-adj-xQOalI4h
  2. Latin, relatif à une personne ou région associée avec les langues dérivées du latin.
    Sense id: fr-Latin-en-adj-LW4DEFcL Categories (other): Exemples en anglais
The following are not (yet) sense-disambiguated
Derived forms: Latin alphabet, Latin America Related terms: Latina, Latino, Latinx, Latin@

Proper name

IPA: \ˈlæt.n̩\, \ˈlæt.ɪn\, ˈlæt.n̩ Audio: En-us-Latin.ogg , LL-Q1860 (eng)-Grendelkhan-Latin.wav
  1. Latin, langue latine. Tags: uncountable
    Sense id: fr-Latin-en-name-2WiJhIGM Categories (other): Langues en anglais, Noms indénombrables en anglais Topics: linguistic
The following are not (yet) sense-disambiguated
Hyponyms: Classical Latin, Late Latin, Liturgical Latin, Medieval Latin, Old Latin, Vulgar Latin

Inflected forms

{
  "categories": [
    {
      "kind": "other",
      "name": "Adjectifs en anglais",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Gentilés en français",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Lemmes en anglais",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Mots en anglais issus d’un mot en latin",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Anglais",
      "orig": "anglais",
      "parents": [],
      "source": "w"
    }
  ],
  "derived": [
    {
      "word": "Latin alphabet"
    },
    {
      "word": "Latin America"
    }
  ],
  "etymology_texts": [
    "Du latin Latinus."
  ],
  "lang": "Anglais",
  "lang_code": "en",
  "pos": "adj",
  "pos_title": "Adjectif",
  "related": [
    {
      "word": "Latina"
    },
    {
      "word": "Latino"
    },
    {
      "word": "Latinx"
    },
    {
      "word": "Latin@"
    }
  ],
  "senses": [
    {
      "glosses": [
        "Latin, relatif à la langue latine."
      ],
      "id": "fr-Latin-en-adj-xQOalI4h"
    },
    {
      "categories": [
        {
          "kind": "other",
          "name": "Exemples en anglais",
          "parents": [],
          "source": "w"
        }
      ],
      "examples": [
        {
          "text": "I’m going out with a real hot-blooded Latin lover.",
          "translation": "Je sors avec un séducteur latino ardent."
        },
        {
          "text": "Latin America.",
          "translation": "Amérique latine."
        }
      ],
      "glosses": [
        "Latin, relatif à une personne ou région associée avec les langues dérivées du latin."
      ],
      "id": "fr-Latin-en-adj-LW4DEFcL"
    }
  ],
  "sounds": [
    {
      "ipa": "\\ˈlæt.n̩\\",
      "raw_tags": [
        "États-Unis"
      ]
    },
    {
      "ipa": "\\ˈlæt.ɪn\\",
      "raw_tags": [
        "Royaume-Uni"
      ]
    },
    {
      "audio": "En-us-Latin.ogg",
      "ipa": "ˈlæt.n̩",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/d/dc/En-us-Latin.ogg/En-us-Latin.ogg.mp3",
      "ogg_url": "https://commons.wikimedia.org/wiki/Special:FilePath/En-us-Latin.ogg",
      "raw_tags": [
        "États-Unis"
      ]
    },
    {
      "audio": "LL-Q1860 (eng)-Grendelkhan-Latin.wav",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/e/e6/LL-Q1860_(eng)-Grendelkhan-Latin.wav/LL-Q1860_(eng)-Grendelkhan-Latin.wav.mp3",
      "ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/e/e6/LL-Q1860_(eng)-Grendelkhan-Latin.wav/LL-Q1860_(eng)-Grendelkhan-Latin.wav.ogg",
      "raw_tags": [
        "Connecticut (États-Unis)"
      ],
      "wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q1860 (eng)-Grendelkhan-Latin.wav"
    }
  ],
  "word": "Latin"
}

{
  "categories": [
    {
      "kind": "other",
      "name": "Gentilés en français",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Mots en anglais issus d’un mot en latin",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Noms propres en anglais",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Anglais",
      "orig": "anglais",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_texts": [
    "Du latin Latinus."
  ],
  "hyponyms": [
    {
      "word": "Classical Latin"
    },
    {
      "word": "Late Latin"
    },
    {
      "word": "Liturgical Latin"
    },
    {
      "word": "Medieval Latin"
    },
    {
      "word": "Old Latin"
    },
    {
      "word": "Vulgar Latin"
    }
  ],
  "lang": "Anglais",
  "lang_code": "en",
  "pos": "name",
  "pos_title": "Nom propre",
  "senses": [
    {
      "categories": [
        {
          "kind": "other",
          "name": "Langues en anglais",
          "parents": [],
          "source": "w"
        },
        {
          "kind": "other",
          "name": "Noms indénombrables en anglais",
          "parents": [],
          "source": "w"
        }
      ],
      "glosses": [
        "Latin, langue latine."
      ],
      "id": "fr-Latin-en-name-2WiJhIGM",
      "tags": [
        "uncountable"
      ],
      "topics": [
        "linguistic"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "\\ˈlæt.n̩\\",
      "raw_tags": [
        "États-Unis"
      ]
    },
    {
      "ipa": "\\ˈlæt.ɪn\\",
      "raw_tags": [
        "Royaume-Uni"
      ]
    },
    {
      "audio": "En-us-Latin.ogg",
      "ipa": "ˈlæt.n̩",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/d/dc/En-us-Latin.ogg/En-us-Latin.ogg.mp3",
      "ogg_url": "https://commons.wikimedia.org/wiki/Special:FilePath/En-us-Latin.ogg",
      "raw_tags": [
        "États-Unis"
      ]
    },
    {
      "audio": "LL-Q1860 (eng)-Grendelkhan-Latin.wav",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/e/e6/LL-Q1860_(eng)-Grendelkhan-Latin.wav/LL-Q1860_(eng)-Grendelkhan-Latin.wav.mp3",
      "ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/e/e6/LL-Q1860_(eng)-Grendelkhan-Latin.wav/LL-Q1860_(eng)-Grendelkhan-Latin.wav.ogg",
      "raw_tags": [
        "Connecticut (États-Unis)"
      ],
      "wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q1860 (eng)-Grendelkhan-Latin.wav"
    }
  ],
  "word": "Latin"
}
{
  "categories": [
    "Adjectifs en anglais",
    "Gentilés en français",
    "Lemmes en anglais",
    "Mots en anglais issus d’un mot en latin",
    "anglais"
  ],
  "derived": [
    {
      "word": "Latin alphabet"
    },
    {
      "word": "Latin America"
    }
  ],
  "etymology_texts": [
    "Du latin Latinus."
  ],
  "lang": "Anglais",
  "lang_code": "en",
  "pos": "adj",
  "pos_title": "Adjectif",
  "related": [
    {
      "word": "Latina"
    },
    {
      "word": "Latino"
    },
    {
      "word": "Latinx"
    },
    {
      "word": "Latin@"
    }
  ],
  "senses": [
    {
      "glosses": [
        "Latin, relatif à la langue latine."
      ]
    },
    {
      "categories": [
        "Exemples en anglais"
      ],
      "examples": [
        {
          "text": "I’m going out with a real hot-blooded Latin lover.",
          "translation": "Je sors avec un séducteur latino ardent."
        },
        {
          "text": "Latin America.",
          "translation": "Amérique latine."
        }
      ],
      "glosses": [
        "Latin, relatif à une personne ou région associée avec les langues dérivées du latin."
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "\\ˈlæt.n̩\\",
      "raw_tags": [
        "États-Unis"
      ]
    },
    {
      "ipa": "\\ˈlæt.ɪn\\",
      "raw_tags": [
        "Royaume-Uni"
      ]
    },
    {
      "audio": "En-us-Latin.ogg",
      "ipa": "ˈlæt.n̩",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/d/dc/En-us-Latin.ogg/En-us-Latin.ogg.mp3",
      "ogg_url": "https://commons.wikimedia.org/wiki/Special:FilePath/En-us-Latin.ogg",
      "raw_tags": [
        "États-Unis"
      ]
    },
    {
      "audio": "LL-Q1860 (eng)-Grendelkhan-Latin.wav",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/e/e6/LL-Q1860_(eng)-Grendelkhan-Latin.wav/LL-Q1860_(eng)-Grendelkhan-Latin.wav.mp3",
      "ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/e/e6/LL-Q1860_(eng)-Grendelkhan-Latin.wav/LL-Q1860_(eng)-Grendelkhan-Latin.wav.ogg",
      "raw_tags": [
        "Connecticut (États-Unis)"
      ],
      "wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q1860 (eng)-Grendelkhan-Latin.wav"
    }
  ],
  "word": "Latin"
}

{
  "categories": [
    "Gentilés en français",
    "Mots en anglais issus d’un mot en latin",
    "Noms propres en anglais",
    "anglais"
  ],
  "etymology_texts": [
    "Du latin Latinus."
  ],
  "hyponyms": [
    {
      "word": "Classical Latin"
    },
    {
      "word": "Late Latin"
    },
    {
      "word": "Liturgical Latin"
    },
    {
      "word": "Medieval Latin"
    },
    {
      "word": "Old Latin"
    },
    {
      "word": "Vulgar Latin"
    }
  ],
  "lang": "Anglais",
  "lang_code": "en",
  "pos": "name",
  "pos_title": "Nom propre",
  "senses": [
    {
      "categories": [
        "Langues en anglais",
        "Noms indénombrables en anglais"
      ],
      "glosses": [
        "Latin, langue latine."
      ],
      "tags": [
        "uncountable"
      ],
      "topics": [
        "linguistic"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "\\ˈlæt.n̩\\",
      "raw_tags": [
        "États-Unis"
      ]
    },
    {
      "ipa": "\\ˈlæt.ɪn\\",
      "raw_tags": [
        "Royaume-Uni"
      ]
    },
    {
      "audio": "En-us-Latin.ogg",
      "ipa": "ˈlæt.n̩",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/d/dc/En-us-Latin.ogg/En-us-Latin.ogg.mp3",
      "ogg_url": "https://commons.wikimedia.org/wiki/Special:FilePath/En-us-Latin.ogg",
      "raw_tags": [
        "États-Unis"
      ]
    },
    {
      "audio": "LL-Q1860 (eng)-Grendelkhan-Latin.wav",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/e/e6/LL-Q1860_(eng)-Grendelkhan-Latin.wav/LL-Q1860_(eng)-Grendelkhan-Latin.wav.mp3",
      "ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/e/e6/LL-Q1860_(eng)-Grendelkhan-Latin.wav/LL-Q1860_(eng)-Grendelkhan-Latin.wav.ogg",
      "raw_tags": [
        "Connecticut (États-Unis)"
      ],
      "wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q1860 (eng)-Grendelkhan-Latin.wav"
    }
  ],
  "word": "Latin"
}

Download raw JSONL data for Latin meaning in Anglais (3.2kB)


This page is a part of the kaikki.org machine-readable Anglais dictionary. This dictionary is based on structured data extracted on 2025-03-02 from the frwiktionary dump dated 2025-03-02 using wiktextract (7dd5d20 and 5a03470). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.