See Diana in All languages combined, or Wiktionary
{
"categories": [
{
"kind": "other",
"name": "Dates manquantes en anglais",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "Mots en anglais issus d’un mot en latin",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "Noms propres en anglais",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "Anglais",
"orig": "anglais",
"parents": [],
"source": "w"
}
],
"etymology_texts": [
"(Date à préciser) Du latin Diana."
],
"lang": "Anglais",
"lang_code": "en",
"pos": "name",
"pos_title": "Nom propre",
"senses": [
{
"categories": [
{
"kind": "other",
"name": "Divinités romaines en anglais",
"parents": [],
"source": "w"
}
],
"glosses": [
"Diane."
],
"id": "fr-Diana-en-name-OkJV7xK8",
"raw_tags": [
"Divinité"
]
}
],
"sounds": [
{
"ipa": "\\daɪˈænə\\"
},
{
"audio": "LL-Q1860 (eng)-Vealhurl-Diana.wav",
"mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/5/5c/LL-Q1860_(eng)-Vealhurl-Diana.wav/LL-Q1860_(eng)-Vealhurl-Diana.wav.mp3",
"ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/5/5c/LL-Q1860_(eng)-Vealhurl-Diana.wav/LL-Q1860_(eng)-Vealhurl-Diana.wav.ogg",
"raw_tags": [
"Sud de l'Angleterre (Royaume-Uni)"
],
"wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q1860 (eng)-Vealhurl-Diana.wav"
},
{
"audio": "LL-Q1860 (eng)-Grendelkhan-Diana.wav",
"mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/0/07/LL-Q1860_(eng)-Grendelkhan-Diana.wav/LL-Q1860_(eng)-Grendelkhan-Diana.wav.mp3",
"ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/0/07/LL-Q1860_(eng)-Grendelkhan-Diana.wav/LL-Q1860_(eng)-Grendelkhan-Diana.wav.ogg",
"raw_tags": [
"Connecticut (États-Unis)"
],
"wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q1860 (eng)-Grendelkhan-Diana.wav"
}
],
"word": "Diana"
}
{
"categories": [
{
"kind": "other",
"name": "Dates manquantes en anglais",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "Mots en anglais issus d’un mot en latin",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "Prénoms féminins en anglais",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "Anglais",
"orig": "anglais",
"parents": [],
"source": "w"
}
],
"etymology_texts": [
"(Date à préciser) Du latin Diana."
],
"lang": "Anglais",
"lang_code": "en",
"pos": "name",
"pos_title": "Prénom",
"senses": [
{
"glosses": [
"Prénom féminin, correspondant à Diane."
],
"id": "fr-Diana-en-name-Q5R87PSl"
}
],
"sounds": [
{
"ipa": "\\daɪˈænə\\"
},
{
"audio": "LL-Q1860 (eng)-Vealhurl-Diana.wav",
"mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/5/5c/LL-Q1860_(eng)-Vealhurl-Diana.wav/LL-Q1860_(eng)-Vealhurl-Diana.wav.mp3",
"ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/5/5c/LL-Q1860_(eng)-Vealhurl-Diana.wav/LL-Q1860_(eng)-Vealhurl-Diana.wav.ogg",
"raw_tags": [
"Sud de l'Angleterre (Royaume-Uni)"
],
"wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q1860 (eng)-Vealhurl-Diana.wav"
},
{
"audio": "LL-Q1860 (eng)-Grendelkhan-Diana.wav",
"mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/0/07/LL-Q1860_(eng)-Grendelkhan-Diana.wav/LL-Q1860_(eng)-Grendelkhan-Diana.wav.mp3",
"ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/0/07/LL-Q1860_(eng)-Grendelkhan-Diana.wav/LL-Q1860_(eng)-Grendelkhan-Diana.wav.ogg",
"raw_tags": [
"Connecticut (États-Unis)"
],
"wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q1860 (eng)-Grendelkhan-Diana.wav"
}
],
"tags": [
"first name"
],
"word": "Diana"
}
{
"categories": [
"Dates manquantes en anglais",
"Mots en anglais issus d’un mot en latin",
"Noms propres en anglais",
"anglais"
],
"etymology_texts": [
"(Date à préciser) Du latin Diana."
],
"lang": "Anglais",
"lang_code": "en",
"pos": "name",
"pos_title": "Nom propre",
"senses": [
{
"categories": [
"Divinités romaines en anglais"
],
"glosses": [
"Diane."
],
"raw_tags": [
"Divinité"
]
}
],
"sounds": [
{
"ipa": "\\daɪˈænə\\"
},
{
"audio": "LL-Q1860 (eng)-Vealhurl-Diana.wav",
"mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/5/5c/LL-Q1860_(eng)-Vealhurl-Diana.wav/LL-Q1860_(eng)-Vealhurl-Diana.wav.mp3",
"ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/5/5c/LL-Q1860_(eng)-Vealhurl-Diana.wav/LL-Q1860_(eng)-Vealhurl-Diana.wav.ogg",
"raw_tags": [
"Sud de l'Angleterre (Royaume-Uni)"
],
"wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q1860 (eng)-Vealhurl-Diana.wav"
},
{
"audio": "LL-Q1860 (eng)-Grendelkhan-Diana.wav",
"mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/0/07/LL-Q1860_(eng)-Grendelkhan-Diana.wav/LL-Q1860_(eng)-Grendelkhan-Diana.wav.mp3",
"ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/0/07/LL-Q1860_(eng)-Grendelkhan-Diana.wav/LL-Q1860_(eng)-Grendelkhan-Diana.wav.ogg",
"raw_tags": [
"Connecticut (États-Unis)"
],
"wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q1860 (eng)-Grendelkhan-Diana.wav"
}
],
"word": "Diana"
}
{
"categories": [
"Dates manquantes en anglais",
"Mots en anglais issus d’un mot en latin",
"Prénoms féminins en anglais",
"anglais"
],
"etymology_texts": [
"(Date à préciser) Du latin Diana."
],
"lang": "Anglais",
"lang_code": "en",
"pos": "name",
"pos_title": "Prénom",
"senses": [
{
"glosses": [
"Prénom féminin, correspondant à Diane."
]
}
],
"sounds": [
{
"ipa": "\\daɪˈænə\\"
},
{
"audio": "LL-Q1860 (eng)-Vealhurl-Diana.wav",
"mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/5/5c/LL-Q1860_(eng)-Vealhurl-Diana.wav/LL-Q1860_(eng)-Vealhurl-Diana.wav.mp3",
"ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/5/5c/LL-Q1860_(eng)-Vealhurl-Diana.wav/LL-Q1860_(eng)-Vealhurl-Diana.wav.ogg",
"raw_tags": [
"Sud de l'Angleterre (Royaume-Uni)"
],
"wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q1860 (eng)-Vealhurl-Diana.wav"
},
{
"audio": "LL-Q1860 (eng)-Grendelkhan-Diana.wav",
"mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/0/07/LL-Q1860_(eng)-Grendelkhan-Diana.wav/LL-Q1860_(eng)-Grendelkhan-Diana.wav.mp3",
"ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/0/07/LL-Q1860_(eng)-Grendelkhan-Diana.wav/LL-Q1860_(eng)-Grendelkhan-Diana.wav.ogg",
"raw_tags": [
"Connecticut (États-Unis)"
],
"wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q1860 (eng)-Grendelkhan-Diana.wav"
}
],
"tags": [
"first name"
],
"word": "Diana"
}
Download raw JSONL data for Diana meaning in Anglais (2.8kB)
This page is a part of the kaikki.org machine-readable Anglais dictionary. This dictionary is based on structured data extracted on 2024-12-21 from the frwiktionary dump dated 2024-12-20 using wiktextract (d8cb2f3 and 4e554ae). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.
If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.