See Argentinian in All languages combined, or Wiktionary
{ "categories": [ { "kind": "other", "name": "Adjectifs en anglais", "parents": [], "source": "w" }, { "kind": "other", "name": "Argentine en anglais", "parents": [], "source": "w" }, { "kind": "other", "name": "Gentilés d’Amérique du Sud en anglais", "parents": [], "source": "w" }, { "kind": "other", "name": "Lemmes en anglais", "parents": [], "source": "w" }, { "kind": "other", "name": "Anglais", "orig": "anglais", "parents": [], "source": "w" } ], "etymology_texts": [ "De Argentina avec le suffixe -ian." ], "lang": "Anglais", "lang_code": "en", "pos": "adj", "pos_title": "Adjectif", "senses": [ { "glosses": [ "Argentin (qui a un rapport avec l’Argentine)." ], "id": "fr-Argentinian-en-adj-~8uie-vB" } ], "sounds": [ { "ipa": "\\ˈɑː.dʒən.ˌtɪn.ɪən\\" }, { "audio": "LL-Q1860 (eng)-Vealhurl-Argentinian.wav", "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/a/a5/LL-Q1860_(eng)-Vealhurl-Argentinian.wav/LL-Q1860_(eng)-Vealhurl-Argentinian.wav.mp3", "ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/a/a5/LL-Q1860_(eng)-Vealhurl-Argentinian.wav/LL-Q1860_(eng)-Vealhurl-Argentinian.wav.ogg", "raw_tags": [ "Sud de l'Angleterre (Royaume-Uni)" ], "wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q1860 (eng)-Vealhurl-Argentinian.wav" } ], "word": "Argentinian" } { "categories": [ { "kind": "other", "name": "Argentine en anglais", "parents": [], "source": "w" }, { "kind": "other", "name": "Gentilés d’Amérique du Sud en anglais", "parents": [], "source": "w" }, { "kind": "other", "name": "Lemmes en anglais", "parents": [], "source": "w" }, { "kind": "other", "name": "Noms communs en anglais", "parents": [], "source": "w" }, { "kind": "other", "name": "Anglais", "orig": "anglais", "parents": [], "source": "w" } ], "etymology_texts": [ "De Argentina avec le suffixe -ian." ], "forms": [ { "form": "Argentinians", "ipas": [ "\\ˈɑː.dʒən.ˌtɪn.ɪənz\\" ], "tags": [ "plural" ] } ], "lang": "Anglais", "lang_code": "en", "pos": "noun", "pos_title": "Nom commun", "senses": [ { "glosses": [ "Argentin (personne argentine)." ], "id": "fr-Argentinian-en-noun-VWPk9v6F" } ], "sounds": [ { "ipa": "\\ˈɑː.dʒən.ˌtɪn.ɪən\\" }, { "audio": "LL-Q1860 (eng)-Vealhurl-Argentinian.wav", "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/a/a5/LL-Q1860_(eng)-Vealhurl-Argentinian.wav/LL-Q1860_(eng)-Vealhurl-Argentinian.wav.mp3", "ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/a/a5/LL-Q1860_(eng)-Vealhurl-Argentinian.wav/LL-Q1860_(eng)-Vealhurl-Argentinian.wav.ogg", "raw_tags": [ "Sud de l'Angleterre (Royaume-Uni)" ], "wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q1860 (eng)-Vealhurl-Argentinian.wav" } ], "synonyms": [ { "word": "Argentine" } ], "word": "Argentinian" }
{ "categories": [ "Adjectifs en anglais", "Argentine en anglais", "Gentilés d’Amérique du Sud en anglais", "Lemmes en anglais", "anglais" ], "etymology_texts": [ "De Argentina avec le suffixe -ian." ], "lang": "Anglais", "lang_code": "en", "pos": "adj", "pos_title": "Adjectif", "senses": [ { "glosses": [ "Argentin (qui a un rapport avec l’Argentine)." ] } ], "sounds": [ { "ipa": "\\ˈɑː.dʒən.ˌtɪn.ɪən\\" }, { "audio": "LL-Q1860 (eng)-Vealhurl-Argentinian.wav", "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/a/a5/LL-Q1860_(eng)-Vealhurl-Argentinian.wav/LL-Q1860_(eng)-Vealhurl-Argentinian.wav.mp3", "ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/a/a5/LL-Q1860_(eng)-Vealhurl-Argentinian.wav/LL-Q1860_(eng)-Vealhurl-Argentinian.wav.ogg", "raw_tags": [ "Sud de l'Angleterre (Royaume-Uni)" ], "wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q1860 (eng)-Vealhurl-Argentinian.wav" } ], "word": "Argentinian" } { "categories": [ "Argentine en anglais", "Gentilés d’Amérique du Sud en anglais", "Lemmes en anglais", "Noms communs en anglais", "anglais" ], "etymology_texts": [ "De Argentina avec le suffixe -ian." ], "forms": [ { "form": "Argentinians", "ipas": [ "\\ˈɑː.dʒən.ˌtɪn.ɪənz\\" ], "tags": [ "plural" ] } ], "lang": "Anglais", "lang_code": "en", "pos": "noun", "pos_title": "Nom commun", "senses": [ { "glosses": [ "Argentin (personne argentine)." ] } ], "sounds": [ { "ipa": "\\ˈɑː.dʒən.ˌtɪn.ɪən\\" }, { "audio": "LL-Q1860 (eng)-Vealhurl-Argentinian.wav", "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/a/a5/LL-Q1860_(eng)-Vealhurl-Argentinian.wav/LL-Q1860_(eng)-Vealhurl-Argentinian.wav.mp3", "ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/a/a5/LL-Q1860_(eng)-Vealhurl-Argentinian.wav/LL-Q1860_(eng)-Vealhurl-Argentinian.wav.ogg", "raw_tags": [ "Sud de l'Angleterre (Royaume-Uni)" ], "wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q1860 (eng)-Vealhurl-Argentinian.wav" } ], "synonyms": [ { "word": "Argentine" } ], "word": "Argentinian" }
Download raw JSONL data for Argentinian meaning in Anglais (2.0kB)
This page is a part of the kaikki.org machine-readable Anglais dictionary. This dictionary is based on structured data extracted on 2024-11-03 from the frwiktionary dump dated 2024-10-20 using wiktextract (d6bf104 and a5af179). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.
If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.