"transform" meaning in All languages combined

See transform on Wiktionary

Noun [Anglais]

IPA: \ˈtɹæns.fɔɹm\, \ˈtɹɑːns.fɔːm\, \ˈtɹæns.fɔɹm\, ˈtɹæns.fɔɹm, \ˈtɹɑːns.fɔːm\, ˈtɹɑːns.fɔːm Audio: En-us-transform.ogg , LL-Q1860 (eng)-Vealhurl-transform (noun).wav Forms: transforms [plural]
  1. Transformation.
    Sense id: fr-transform-en-noun-wqg758~q
  2. Transformée.
    Sense id: fr-transform-en-noun-y1Dhv8cn Categories (other): Exemples en anglais, Lexique en anglais des mathématiques Topics: mathematics
The following are not (yet) sense-disambiguated

Verb [Anglais]

IPA: \tɹæns.ˈfɔɹm\, \tɹɑːns.ˈfɔːm\, \ˈtɹæns.fɔɹm\, ˈtɹæns.fɔɹm, \ˈtɹɑːns.fɔːm\, ˈtɹɑːns.fɔːm Audio: En-us-transform.ogg , LL-Q1860 (eng)-Vealhurl-transform (noun).wav Forms: to transform [infinitive], transforms [present, third-person, singular], transformed [preterite], transformed [participle, past], transforming [participle, present]
  1. Transformer. Tags: transitive
    Sense id: fr-transform-en-verb-4rp6lAky Categories (other): Verbes transitifs en anglais
  2. Se transformer. Tags: intransitive
    Sense id: fr-transform-en-verb-O-~S5Fjz Categories (other): Verbes intransitifs en anglais
The following are not (yet) sense-disambiguated
Derived forms: transformation, transformer

Inflected forms

{
  "categories": [
    {
      "kind": "other",
      "name": "Homographes non homophones en anglais",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Lemmes en anglais",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Mots en anglais issus d’un mot en moyen français",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Verbes en anglais",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Anglais",
      "orig": "anglais",
      "parents": [],
      "source": "w"
    }
  ],
  "derived": [
    {
      "word": "transformation"
    },
    {
      "word": "transformer"
    }
  ],
  "etymology_texts": [
    "(xivᵉ siècle) Du moyen français transformer"
  ],
  "forms": [
    {
      "form": "to transform",
      "ipas": [
        "\\tɹæns.ˈfɔɹm\\",
        "\\tɹɑːns.ˈfɔːm\\"
      ],
      "tags": [
        "infinitive"
      ]
    },
    {
      "form": "transforms",
      "ipas": [
        "\\tɹæns.ˈfɔɹmz\\",
        "\\tɹɑːns.ˈfɔːmz\\"
      ],
      "tags": [
        "present",
        "third-person",
        "singular"
      ]
    },
    {
      "form": "transformed",
      "ipas": [
        "\\tɹæns.ˈfɔɹmd\\",
        "\\tɹɑːns.ˈfɔːmd\\"
      ],
      "tags": [
        "preterite"
      ]
    },
    {
      "form": "transformed",
      "ipas": [
        "\\tɹæns.ˈfɔɹmd\\",
        "\\tɹɑːns.ˈfɔːmd\\"
      ],
      "tags": [
        "participle",
        "past"
      ]
    },
    {
      "form": "transforming",
      "ipas": [
        "\\tɹæns.ˈfɔɹ.mɪŋ\\",
        "\\tɹɑːns.ˈfɔː.mɪŋ\\"
      ],
      "tags": [
        "participle",
        "present"
      ]
    }
  ],
  "lang": "Anglais",
  "lang_code": "en",
  "pos": "verb",
  "pos_title": "Verbe",
  "senses": [
    {
      "categories": [
        {
          "kind": "other",
          "name": "Verbes transitifs en anglais",
          "parents": [],
          "source": "w"
        }
      ],
      "glosses": [
        "Transformer."
      ],
      "id": "fr-transform-en-verb-4rp6lAky",
      "tags": [
        "transitive"
      ]
    },
    {
      "categories": [
        {
          "kind": "other",
          "name": "Verbes intransitifs en anglais",
          "parents": [],
          "source": "w"
        }
      ],
      "glosses": [
        "Se transformer."
      ],
      "id": "fr-transform-en-verb-O-~S5Fjz",
      "tags": [
        "intransitive"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "\\tɹæns.ˈfɔɹm\\",
      "raw_tags": [
        "États-Unis"
      ]
    },
    {
      "ipa": "\\tɹɑːns.ˈfɔːm\\",
      "raw_tags": [
        "Royaume-Uni"
      ]
    },
    {
      "ipa": "\\ˈtɹæns.fɔɹm\\"
    },
    {
      "audio": "En-us-transform.ogg",
      "ipa": "ˈtɹæns.fɔɹm",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/d/d0/En-us-transform.ogg/En-us-transform.ogg.mp3",
      "ogg_url": "https://commons.wikimedia.org/wiki/Special:FilePath/En-us-transform.ogg",
      "raw_tags": [
        "(États-Unis)",
        "États-Unis"
      ]
    },
    {
      "ipa": "\\ˈtɹɑːns.fɔːm\\"
    },
    {
      "audio": "LL-Q1860 (eng)-Vealhurl-transform (noun).wav",
      "ipa": "ˈtɹɑːns.fɔːm",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/f/f8/LL-Q1860_(eng)-Vealhurl-transform_(noun).wav/LL-Q1860_(eng)-Vealhurl-transform_(noun).wav.mp3",
      "ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/f/f8/LL-Q1860_(eng)-Vealhurl-transform_(noun).wav/LL-Q1860_(eng)-Vealhurl-transform_(noun).wav.ogg",
      "raw_tags": [
        "(Royaume-Uni)",
        "Royaume-Uni (Sud de l'Angleterre)"
      ],
      "wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q1860 (eng)-Vealhurl-transform (noun).wav"
    }
  ],
  "word": "transform"
}

{
  "categories": [
    {
      "kind": "other",
      "name": "Homographes non homophones en anglais",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Lemmes en anglais",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Mots en anglais issus d’un mot en moyen français",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Noms communs en anglais",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Anglais",
      "orig": "anglais",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_texts": [
    "(xivᵉ siècle) Du moyen français transformer"
  ],
  "forms": [
    {
      "form": "transforms",
      "ipas": [
        "\\ˈtɹæns.fɔɹmz\\",
        "\\ˈtɹɑːns.fɔːmz\\"
      ],
      "tags": [
        "plural"
      ]
    }
  ],
  "lang": "Anglais",
  "lang_code": "en",
  "pos": "noun",
  "pos_title": "Nom commun",
  "senses": [
    {
      "glosses": [
        "Transformation."
      ],
      "id": "fr-transform-en-noun-wqg758~q"
    },
    {
      "categories": [
        {
          "kind": "other",
          "name": "Exemples en anglais",
          "parents": [],
          "source": "w"
        },
        {
          "kind": "other",
          "name": "Lexique en anglais des mathématiques",
          "parents": [],
          "source": "w"
        }
      ],
      "examples": [
        {
          "text": "The Fourier transform.",
          "translation": "La transformée de Fourier."
        }
      ],
      "glosses": [
        "Transformée."
      ],
      "id": "fr-transform-en-noun-y1Dhv8cn",
      "topics": [
        "mathematics"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "\\ˈtɹæns.fɔɹm\\",
      "raw_tags": [
        "États-Unis"
      ]
    },
    {
      "ipa": "\\ˈtɹɑːns.fɔːm\\",
      "raw_tags": [
        "Royaume-Uni"
      ]
    },
    {
      "ipa": "\\ˈtɹæns.fɔɹm\\"
    },
    {
      "audio": "En-us-transform.ogg",
      "ipa": "ˈtɹæns.fɔɹm",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/d/d0/En-us-transform.ogg/En-us-transform.ogg.mp3",
      "ogg_url": "https://commons.wikimedia.org/wiki/Special:FilePath/En-us-transform.ogg",
      "raw_tags": [
        "(États-Unis)",
        "États-Unis"
      ]
    },
    {
      "ipa": "\\ˈtɹɑːns.fɔːm\\"
    },
    {
      "audio": "LL-Q1860 (eng)-Vealhurl-transform (noun).wav",
      "ipa": "ˈtɹɑːns.fɔːm",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/f/f8/LL-Q1860_(eng)-Vealhurl-transform_(noun).wav/LL-Q1860_(eng)-Vealhurl-transform_(noun).wav.mp3",
      "ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/f/f8/LL-Q1860_(eng)-Vealhurl-transform_(noun).wav/LL-Q1860_(eng)-Vealhurl-transform_(noun).wav.ogg",
      "raw_tags": [
        "(Royaume-Uni)",
        "Royaume-Uni (Sud de l'Angleterre)"
      ],
      "wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q1860 (eng)-Vealhurl-transform (noun).wav"
    }
  ],
  "word": "transform"
}
{
  "categories": [
    "Homographes non homophones en anglais",
    "Lemmes en anglais",
    "Mots en anglais issus d’un mot en moyen français",
    "Verbes en anglais",
    "anglais"
  ],
  "derived": [
    {
      "word": "transformation"
    },
    {
      "word": "transformer"
    }
  ],
  "etymology_texts": [
    "(xivᵉ siècle) Du moyen français transformer"
  ],
  "forms": [
    {
      "form": "to transform",
      "ipas": [
        "\\tɹæns.ˈfɔɹm\\",
        "\\tɹɑːns.ˈfɔːm\\"
      ],
      "tags": [
        "infinitive"
      ]
    },
    {
      "form": "transforms",
      "ipas": [
        "\\tɹæns.ˈfɔɹmz\\",
        "\\tɹɑːns.ˈfɔːmz\\"
      ],
      "tags": [
        "present",
        "third-person",
        "singular"
      ]
    },
    {
      "form": "transformed",
      "ipas": [
        "\\tɹæns.ˈfɔɹmd\\",
        "\\tɹɑːns.ˈfɔːmd\\"
      ],
      "tags": [
        "preterite"
      ]
    },
    {
      "form": "transformed",
      "ipas": [
        "\\tɹæns.ˈfɔɹmd\\",
        "\\tɹɑːns.ˈfɔːmd\\"
      ],
      "tags": [
        "participle",
        "past"
      ]
    },
    {
      "form": "transforming",
      "ipas": [
        "\\tɹæns.ˈfɔɹ.mɪŋ\\",
        "\\tɹɑːns.ˈfɔː.mɪŋ\\"
      ],
      "tags": [
        "participle",
        "present"
      ]
    }
  ],
  "lang": "Anglais",
  "lang_code": "en",
  "pos": "verb",
  "pos_title": "Verbe",
  "senses": [
    {
      "categories": [
        "Verbes transitifs en anglais"
      ],
      "glosses": [
        "Transformer."
      ],
      "tags": [
        "transitive"
      ]
    },
    {
      "categories": [
        "Verbes intransitifs en anglais"
      ],
      "glosses": [
        "Se transformer."
      ],
      "tags": [
        "intransitive"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "\\tɹæns.ˈfɔɹm\\",
      "raw_tags": [
        "États-Unis"
      ]
    },
    {
      "ipa": "\\tɹɑːns.ˈfɔːm\\",
      "raw_tags": [
        "Royaume-Uni"
      ]
    },
    {
      "ipa": "\\ˈtɹæns.fɔɹm\\"
    },
    {
      "audio": "En-us-transform.ogg",
      "ipa": "ˈtɹæns.fɔɹm",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/d/d0/En-us-transform.ogg/En-us-transform.ogg.mp3",
      "ogg_url": "https://commons.wikimedia.org/wiki/Special:FilePath/En-us-transform.ogg",
      "raw_tags": [
        "(États-Unis)",
        "États-Unis"
      ]
    },
    {
      "ipa": "\\ˈtɹɑːns.fɔːm\\"
    },
    {
      "audio": "LL-Q1860 (eng)-Vealhurl-transform (noun).wav",
      "ipa": "ˈtɹɑːns.fɔːm",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/f/f8/LL-Q1860_(eng)-Vealhurl-transform_(noun).wav/LL-Q1860_(eng)-Vealhurl-transform_(noun).wav.mp3",
      "ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/f/f8/LL-Q1860_(eng)-Vealhurl-transform_(noun).wav/LL-Q1860_(eng)-Vealhurl-transform_(noun).wav.ogg",
      "raw_tags": [
        "(Royaume-Uni)",
        "Royaume-Uni (Sud de l'Angleterre)"
      ],
      "wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q1860 (eng)-Vealhurl-transform (noun).wav"
    }
  ],
  "word": "transform"
}

{
  "categories": [
    "Homographes non homophones en anglais",
    "Lemmes en anglais",
    "Mots en anglais issus d’un mot en moyen français",
    "Noms communs en anglais",
    "anglais"
  ],
  "etymology_texts": [
    "(xivᵉ siècle) Du moyen français transformer"
  ],
  "forms": [
    {
      "form": "transforms",
      "ipas": [
        "\\ˈtɹæns.fɔɹmz\\",
        "\\ˈtɹɑːns.fɔːmz\\"
      ],
      "tags": [
        "plural"
      ]
    }
  ],
  "lang": "Anglais",
  "lang_code": "en",
  "pos": "noun",
  "pos_title": "Nom commun",
  "senses": [
    {
      "glosses": [
        "Transformation."
      ]
    },
    {
      "categories": [
        "Exemples en anglais",
        "Lexique en anglais des mathématiques"
      ],
      "examples": [
        {
          "text": "The Fourier transform.",
          "translation": "La transformée de Fourier."
        }
      ],
      "glosses": [
        "Transformée."
      ],
      "topics": [
        "mathematics"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "\\ˈtɹæns.fɔɹm\\",
      "raw_tags": [
        "États-Unis"
      ]
    },
    {
      "ipa": "\\ˈtɹɑːns.fɔːm\\",
      "raw_tags": [
        "Royaume-Uni"
      ]
    },
    {
      "ipa": "\\ˈtɹæns.fɔɹm\\"
    },
    {
      "audio": "En-us-transform.ogg",
      "ipa": "ˈtɹæns.fɔɹm",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/d/d0/En-us-transform.ogg/En-us-transform.ogg.mp3",
      "ogg_url": "https://commons.wikimedia.org/wiki/Special:FilePath/En-us-transform.ogg",
      "raw_tags": [
        "(États-Unis)",
        "États-Unis"
      ]
    },
    {
      "ipa": "\\ˈtɹɑːns.fɔːm\\"
    },
    {
      "audio": "LL-Q1860 (eng)-Vealhurl-transform (noun).wav",
      "ipa": "ˈtɹɑːns.fɔːm",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/f/f8/LL-Q1860_(eng)-Vealhurl-transform_(noun).wav/LL-Q1860_(eng)-Vealhurl-transform_(noun).wav.mp3",
      "ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/f/f8/LL-Q1860_(eng)-Vealhurl-transform_(noun).wav/LL-Q1860_(eng)-Vealhurl-transform_(noun).wav.ogg",
      "raw_tags": [
        "(Royaume-Uni)",
        "Royaume-Uni (Sud de l'Angleterre)"
      ],
      "wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q1860 (eng)-Vealhurl-transform (noun).wav"
    }
  ],
  "word": "transform"
}

Download raw JSONL data for transform meaning in All languages combined (4.1kB)


This page is a part of the kaikki.org machine-readable All languages combined dictionary. This dictionary is based on structured data extracted on 2025-02-21 from the frwiktionary dump dated 2025-02-21 using wiktextract (9e2b7d3 and f2e72e5). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.