See abrogatione on Wiktionary
{
"categories": [
{
"kind": "other",
"name": "Formes de noms communs en latin",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "Latin",
"orig": "latin",
"parents": [],
"source": "w"
}
],
"lang": "Latin",
"lang_code": "la",
"pos": "noun",
"pos_title": "Forme de nom commun",
"senses": [
{
"form_of": [
{
"word": "abrogatio"
}
],
"glosses": [
"Ablatif singulier de abrogatio."
],
"id": "fr-abrogatione-la-noun-CNgJ0Otm"
}
],
"tags": [
"form-of"
],
"word": "abrogatione"
}
{
"categories": [
"Formes de noms communs en latin",
"latin"
],
"lang": "Latin",
"lang_code": "la",
"pos": "noun",
"pos_title": "Forme de nom commun",
"senses": [
{
"form_of": [
{
"word": "abrogatio"
}
],
"glosses": [
"Ablatif singulier de abrogatio."
]
}
],
"tags": [
"form-of"
],
"word": "abrogatione"
}
Download raw JSONL data for abrogatione meaning in All languages combined (0.3kB)
This page is a part of the kaikki.org machine-readable All languages combined dictionary. This dictionary is based on structured data extracted on 2024-09-27 from the frwiktionary dump dated 2024-09-20 using wiktextract (3f344ef and 66545a6). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.
If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.