"Pirandello" meaning in All languages combined

See Pirandello on Wiktionary

Proper name [Français]

  1. Nom de famille italien.
    Sense id: fr-Pirandello-fr-name-95zkYloS
The following are not (yet) sense-disambiguated
Derived forms: pirandellien, pirandellienne

Proper name [Italien]

IPA: \pi.ran.ˈdɛl.lo\ Audio: LL-Q652 (ita)-XANA000-Pirandello.wav
  1. Nom de famille italien
    Sense id: fr-Pirandello-it-name-BQt5ayui
The following are not (yet) sense-disambiguated
Categories (other): Noms de famille en italien, Italien

Proper name [Italien]

Audio: LL-Q652 (ita)-XANA000-Pirandello.wav
  1. Hameau de Agrigente, localité italienne de Sicile.
    Sense id: fr-Pirandello-it-name-jEl4HIr5 Categories (other): Localités de Sicile en italien, Wiktionnaire:Exemples manquants en italien Topics: geography
The following are not (yet) sense-disambiguated
Categories (other): Noms propres en italien, Italien
{
  "categories": [
    {
      "kind": "other",
      "name": "Noms de famille en français",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Wiktionnaire:Étymologies manquantes en français",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Français",
      "orig": "français",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Éponymes en français",
      "parents": [],
      "source": "w"
    }
  ],
  "derived": [
    {
      "word": "pirandellien"
    },
    {
      "word": "pirandellienne"
    }
  ],
  "etymology_texts": [
    "Étymologie manquante ou incomplète. Si vous la connaissez, vous pouvez l’ajouter en cliquant ici."
  ],
  "lang": "Français",
  "lang_code": "fr",
  "pos": "name",
  "pos_title": "Nom de famille",
  "senses": [
    {
      "glosses": [
        "Nom de famille italien."
      ],
      "id": "fr-Pirandello-fr-name-95zkYloS"
    }
  ],
  "tags": [
    "surename"
  ],
  "word": "Pirandello"
}

{
  "categories": [
    {
      "kind": "other",
      "name": "Noms de famille en italien",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Italien",
      "orig": "italien",
      "parents": [],
      "source": "w"
    }
  ],
  "lang": "Italien",
  "lang_code": "it",
  "pos": "name",
  "pos_title": "Nom de famille",
  "senses": [
    {
      "glosses": [
        "Nom de famille italien"
      ],
      "id": "fr-Pirandello-it-name-BQt5ayui"
    }
  ],
  "sounds": [
    {
      "ipa": "\\pi.ran.ˈdɛl.lo\\"
    },
    {
      "audio": "LL-Q652 (ita)-XANA000-Pirandello.wav",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/3/33/LL-Q652_(ita)-XANA000-Pirandello.wav/LL-Q652_(ita)-XANA000-Pirandello.wav.mp3",
      "ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/3/33/LL-Q652_(ita)-XANA000-Pirandello.wav/LL-Q652_(ita)-XANA000-Pirandello.wav.ogg",
      "raw_tags": [
        "Monopoli (Italie)"
      ],
      "wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q652 (ita)-XANA000-Pirandello.wav"
    }
  ],
  "tags": [
    "surename"
  ],
  "word": "Pirandello"
}

{
  "categories": [
    {
      "kind": "other",
      "name": "Noms propres en italien",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Italien",
      "orig": "italien",
      "parents": [],
      "source": "w"
    }
  ],
  "lang": "Italien",
  "lang_code": "it",
  "pos": "name",
  "pos_title": "Nom propre",
  "senses": [
    {
      "categories": [
        {
          "kind": "other",
          "name": "Localités de Sicile en italien",
          "parents": [],
          "source": "w"
        },
        {
          "kind": "other",
          "name": "Wiktionnaire:Exemples manquants en italien",
          "parents": [],
          "source": "w"
        }
      ],
      "glosses": [
        "Hameau de Agrigente, localité italienne de Sicile."
      ],
      "id": "fr-Pirandello-it-name-jEl4HIr5",
      "topics": [
        "geography"
      ]
    }
  ],
  "sounds": [
    {
      "audio": "LL-Q652 (ita)-XANA000-Pirandello.wav",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/3/33/LL-Q652_(ita)-XANA000-Pirandello.wav/LL-Q652_(ita)-XANA000-Pirandello.wav.mp3",
      "ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/3/33/LL-Q652_(ita)-XANA000-Pirandello.wav/LL-Q652_(ita)-XANA000-Pirandello.wav.ogg",
      "raw_tags": [
        "Monopoli (Italie)"
      ],
      "wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q652 (ita)-XANA000-Pirandello.wav"
    }
  ],
  "word": "Pirandello"
}
{
  "categories": [
    "Noms de famille en français",
    "Wiktionnaire:Étymologies manquantes en français",
    "français",
    "Éponymes en français"
  ],
  "derived": [
    {
      "word": "pirandellien"
    },
    {
      "word": "pirandellienne"
    }
  ],
  "etymology_texts": [
    "Étymologie manquante ou incomplète. Si vous la connaissez, vous pouvez l’ajouter en cliquant ici."
  ],
  "lang": "Français",
  "lang_code": "fr",
  "pos": "name",
  "pos_title": "Nom de famille",
  "senses": [
    {
      "glosses": [
        "Nom de famille italien."
      ]
    }
  ],
  "tags": [
    "surename"
  ],
  "word": "Pirandello"
}

{
  "categories": [
    "Noms de famille en italien",
    "italien"
  ],
  "lang": "Italien",
  "lang_code": "it",
  "pos": "name",
  "pos_title": "Nom de famille",
  "senses": [
    {
      "glosses": [
        "Nom de famille italien"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "\\pi.ran.ˈdɛl.lo\\"
    },
    {
      "audio": "LL-Q652 (ita)-XANA000-Pirandello.wav",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/3/33/LL-Q652_(ita)-XANA000-Pirandello.wav/LL-Q652_(ita)-XANA000-Pirandello.wav.mp3",
      "ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/3/33/LL-Q652_(ita)-XANA000-Pirandello.wav/LL-Q652_(ita)-XANA000-Pirandello.wav.ogg",
      "raw_tags": [
        "Monopoli (Italie)"
      ],
      "wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q652 (ita)-XANA000-Pirandello.wav"
    }
  ],
  "tags": [
    "surename"
  ],
  "word": "Pirandello"
}

{
  "categories": [
    "Noms propres en italien",
    "italien"
  ],
  "lang": "Italien",
  "lang_code": "it",
  "pos": "name",
  "pos_title": "Nom propre",
  "senses": [
    {
      "categories": [
        "Localités de Sicile en italien",
        "Wiktionnaire:Exemples manquants en italien"
      ],
      "glosses": [
        "Hameau de Agrigente, localité italienne de Sicile."
      ],
      "topics": [
        "geography"
      ]
    }
  ],
  "sounds": [
    {
      "audio": "LL-Q652 (ita)-XANA000-Pirandello.wav",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/3/33/LL-Q652_(ita)-XANA000-Pirandello.wav/LL-Q652_(ita)-XANA000-Pirandello.wav.mp3",
      "ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/3/33/LL-Q652_(ita)-XANA000-Pirandello.wav/LL-Q652_(ita)-XANA000-Pirandello.wav.ogg",
      "raw_tags": [
        "Monopoli (Italie)"
      ],
      "wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q652 (ita)-XANA000-Pirandello.wav"
    }
  ],
  "word": "Pirandello"
}

Download raw JSONL data for Pirandello meaning in All languages combined (2.1kB)


This page is a part of the kaikki.org machine-readable All languages combined dictionary. This dictionary is based on structured data extracted on 2024-08-26 from the frwiktionary dump dated 2024-08-20 using wiktextract (c15dac4 and c9bbad3). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.