"Ariadna" meaning in Español

See Ariadna in All languages combined, or Wiktionary

Proper name

IPA: [aˈɾjað̞.na]
Rhymes: ad.na Etymology: Del griego antiguo Ἀριάδνη (Ariádnē), personaje mitológico griego que ayudó a Teseo a derrotar al Minotauro. Etymology templates: {{etimología|grc|Ἀριάδνη|tr=Ariádnē}} Del griego antiguo Ἀριάδνη (Ariádnē)
  1. Nombre de pila de mujer .
    Sense id: es-Ariadna-es-name-LCg7Fo04 Categories (other): ES:Antropónimos, ES:Antropónimos femeninos
The following are not (yet) sense-disambiguated
Translations: Ariane (Francés), Ariadne (Inglés), Ariana (Inglés), Ariane (Inglés), Arianna (Inglés), Arianna (Italiano)
{
  "categories": [
    {
      "kind": "other",
      "name": "ES:Sustantivos",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "ES:Sustantivos propios",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Español",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Español-Francés",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Español-Inglés",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Español-Italiano",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_templates": [
    {
      "args": {
        "1": "grc",
        "2": "Ἀριάδνη",
        "tr": "Ariádnē"
      },
      "expansion": "Del griego antiguo Ἀριάδνη (Ariádnē)",
      "name": "etimología"
    }
  ],
  "etymology_text": "Del griego antiguo Ἀριάδνη (Ariádnē), personaje mitológico griego que ayudó a Teseo a derrotar al Minotauro.",
  "extra_sounds": {
    "acentuación": "llana",
    "longitud silábica": "trisílaba"
  },
  "lang": "Español",
  "lang_code": "es",
  "pos": "name",
  "pos_title": "sustantivo propio",
  "senses": [
    {
      "categories": [
        {
          "kind": "other",
          "name": "ES:Antropónimos",
          "parents": [],
          "source": "w"
        },
        {
          "kind": "other",
          "name": "ES:Antropónimos femeninos",
          "parents": [],
          "source": "w"
        }
      ],
      "glosses": [
        "Nombre de pila de mujer\n."
      ],
      "id": "es-Ariadna-es-name-LCg7Fo04",
      "sense_index": "1"
    }
  ],
  "sounds": [
    {
      "ipa": "[aˈɾjað̞.na]"
    },
    {
      "syllabic": "a-riad-na"
    },
    {
      "rhymes": "ad.na"
    }
  ],
  "translations": [
    {
      "lang": "Francés",
      "lang_code": "fr",
      "sense_index": "1",
      "word": "Ariane"
    },
    {
      "lang": "Inglés",
      "lang_code": "en",
      "sense_index": "1",
      "word": "Ariadne"
    },
    {
      "lang": "Inglés",
      "lang_code": "en",
      "sense_index": "1",
      "word": "Ariana"
    },
    {
      "lang": "Inglés",
      "lang_code": "en",
      "sense_index": "1",
      "word": "Ariane"
    },
    {
      "lang": "Inglés",
      "lang_code": "en",
      "sense_index": "1",
      "word": "Arianna"
    },
    {
      "lang": "Italiano",
      "lang_code": "it",
      "sense_index": "1",
      "word": "Arianna"
    }
  ],
  "word": "Ariadna"
}
{
  "categories": [
    "ES:Sustantivos",
    "ES:Sustantivos propios",
    "Español",
    "Español-Francés",
    "Español-Inglés",
    "Español-Italiano"
  ],
  "etymology_templates": [
    {
      "args": {
        "1": "grc",
        "2": "Ἀριάδνη",
        "tr": "Ariádnē"
      },
      "expansion": "Del griego antiguo Ἀριάδνη (Ariádnē)",
      "name": "etimología"
    }
  ],
  "etymology_text": "Del griego antiguo Ἀριάδνη (Ariádnē), personaje mitológico griego que ayudó a Teseo a derrotar al Minotauro.",
  "extra_sounds": {
    "acentuación": "llana",
    "longitud silábica": "trisílaba"
  },
  "lang": "Español",
  "lang_code": "es",
  "pos": "name",
  "pos_title": "sustantivo propio",
  "senses": [
    {
      "categories": [
        "ES:Antropónimos",
        "ES:Antropónimos femeninos"
      ],
      "glosses": [
        "Nombre de pila de mujer\n."
      ],
      "sense_index": "1"
    }
  ],
  "sounds": [
    {
      "ipa": "[aˈɾjað̞.na]"
    },
    {
      "syllabic": "a-riad-na"
    },
    {
      "rhymes": "ad.na"
    }
  ],
  "translations": [
    {
      "lang": "Francés",
      "lang_code": "fr",
      "sense_index": "1",
      "word": "Ariane"
    },
    {
      "lang": "Inglés",
      "lang_code": "en",
      "sense_index": "1",
      "word": "Ariadne"
    },
    {
      "lang": "Inglés",
      "lang_code": "en",
      "sense_index": "1",
      "word": "Ariana"
    },
    {
      "lang": "Inglés",
      "lang_code": "en",
      "sense_index": "1",
      "word": "Ariane"
    },
    {
      "lang": "Inglés",
      "lang_code": "en",
      "sense_index": "1",
      "word": "Arianna"
    },
    {
      "lang": "Italiano",
      "lang_code": "it",
      "sense_index": "1",
      "word": "Arianna"
    }
  ],
  "word": "Ariadna"
}

Download raw JSONL data for Ariadna meaning in Español (1.3kB)

{
  "called_from": "extractor/es/page/process_group/102",
  "msg": "Found unexpected group specifying a sense: [<TEMPLATE(['hipocorísticos'], ['Ari']){} >],head template hipocorísticos",
  "path": [
    "Ariadna"
  ],
  "section": "Español",
  "subsection": "sustantivo propio",
  "title": "Ariadna",
  "trace": ""
}

This page is a part of the kaikki.org machine-readable Español dictionary. This dictionary is based on structured data extracted on 2024-10-01 from the eswiktionary dump dated 2024-09-20 using wiktextract (3fd8a50 and 59b8406). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.