"изумруд" meaning in All languages combined

See изумруд on Wiktionary

Noun [Mari oriental]

  1. Esmeralda.
    Sense id: es-изумруд-mhr-noun-IXixP1b4
The following are not (yet) sense-disambiguated

Noun [Ruso]

IPA: [ɪzʊmˈrut]
Rhymes: ut Etymology: Calco del persa زمرد (zomorrod).
  1. Esmeralda.
    Sense id: es-изумруд-ru-noun-IXixP1b4
The following are not (yet) sense-disambiguated
{
  "categories": [
    {
      "kind": "other",
      "name": "MHR:Palabras de etimología sin precisar",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "MHR:Palabras sin transcripción fonética",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "MHR:Sustantivos",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Mari oriental",
      "parents": [],
      "source": "w"
    }
  ],
  "extra_sounds": {
    "pronunciación": "falta agregar"
  },
  "lang": "Mari oriental",
  "lang_code": "mhr",
  "pos": "noun",
  "pos_title": "Sustantivo",
  "senses": [
    {
      "glosses": [
        "Esmeralda."
      ],
      "id": "es-изумруд-mhr-noun-IXixP1b4",
      "sense_index": "1"
    }
  ],
  "word": "изумруд"
}

{
  "categories": [
    {
      "kind": "other",
      "name": "RU:Palabras formadas por calco",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "RU:Palabras provenientes del persa",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "RU:Rimas:ut",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "RU:Sustantivos",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Ruso",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_text": "Calco del persa زمرد (zomorrod).",
  "lang": "Ruso",
  "lang_code": "ru",
  "pos": "noun",
  "pos_title": "Sustantivo",
  "senses": [
    {
      "glosses": [
        "Esmeralda."
      ],
      "id": "es-изумруд-ru-noun-IXixP1b4",
      "sense_index": "1"
    }
  ],
  "sounds": [
    {
      "ipa": "[ɪzʊmˈrut]"
    },
    {
      "rhymes": "ut"
    }
  ],
  "word": "изумруд"
}
{
  "categories": [
    "MHR:Palabras de etimología sin precisar",
    "MHR:Palabras sin transcripción fonética",
    "MHR:Sustantivos",
    "Mari oriental"
  ],
  "extra_sounds": {
    "pronunciación": "falta agregar"
  },
  "lang": "Mari oriental",
  "lang_code": "mhr",
  "pos": "noun",
  "pos_title": "Sustantivo",
  "senses": [
    {
      "glosses": [
        "Esmeralda."
      ],
      "sense_index": "1"
    }
  ],
  "word": "изумруд"
}

{
  "categories": [
    "RU:Palabras formadas por calco",
    "RU:Palabras provenientes del persa",
    "RU:Rimas:ut",
    "RU:Sustantivos",
    "Ruso"
  ],
  "etymology_text": "Calco del persa زمرد (zomorrod).",
  "lang": "Ruso",
  "lang_code": "ru",
  "pos": "noun",
  "pos_title": "Sustantivo",
  "senses": [
    {
      "glosses": [
        "Esmeralda."
      ],
      "sense_index": "1"
    }
  ],
  "sounds": [
    {
      "ipa": "[ɪzʊmˈrut]"
    },
    {
      "rhymes": "ut"
    }
  ],
  "word": "изумруд"
}

Download raw JSONL data for изумруд meaning in All languages combined (0.8kB)


This page is a part of the kaikki.org machine-readable All languages combined dictionary. This dictionary is based on structured data extracted on 2025-08-06 from the eswiktionary dump dated 2025-08-01 using wiktextract (8b3c49c and 3c020d2). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.