"сброду" meaning in Russian

See сброду in All languages combined, or Wiktionary

Noun

IPA: [ˈzbrodʊ] Forms: сбро́ду [canonical], sbródu [romanization]
Head templates: {{head|ru|noun form|g=m-in|head=сбро́ду}} сбро́ду • (sbródu) m inan
  1. dative singular of сброд (sbrod) Tags: dative, form-of, singular Form of: сброд (extra: sbrod)
    Sense id: en-сброду-ru-noun-aQQZ3OJa Categories (other): Pages with 1 entry, Pages with entries, Russian entries with incorrect language header
{
  "forms": [
    {
      "form": "сбро́ду",
      "tags": [
        "canonical"
      ]
    },
    {
      "form": "sbródu",
      "tags": [
        "romanization"
      ]
    }
  ],
  "head_templates": [
    {
      "args": {
        "1": "ru",
        "2": "noun form",
        "g": "m-in",
        "head": "сбро́ду"
      },
      "expansion": "сбро́ду • (sbródu) m inan",
      "name": "head"
    }
  ],
  "lang": "Russian",
  "lang_code": "ru",
  "pos": "noun",
  "senses": [
    {
      "categories": [
        {
          "kind": "other",
          "name": "Pages with 1 entry",
          "parents": [],
          "source": "w"
        },
        {
          "kind": "other",
          "name": "Pages with entries",
          "parents": [],
          "source": "w"
        },
        {
          "kind": "other",
          "name": "Russian entries with incorrect language header",
          "parents": [
            "Entries with incorrect language header",
            "Entry maintenance"
          ],
          "source": "w"
        }
      ],
      "form_of": [
        {
          "extra": "sbrod",
          "word": "сброд"
        }
      ],
      "glosses": [
        "dative singular of сброд (sbrod)"
      ],
      "id": "en-сброду-ru-noun-aQQZ3OJa",
      "links": [
        [
          "сброд",
          "сброд#Russian"
        ]
      ],
      "tags": [
        "dative",
        "form-of",
        "singular"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "[ˈzbrodʊ]"
    }
  ],
  "word": "сброду"
}
{
  "forms": [
    {
      "form": "сбро́ду",
      "tags": [
        "canonical"
      ]
    },
    {
      "form": "sbródu",
      "tags": [
        "romanization"
      ]
    }
  ],
  "head_templates": [
    {
      "args": {
        "1": "ru",
        "2": "noun form",
        "g": "m-in",
        "head": "сбро́ду"
      },
      "expansion": "сбро́ду • (sbródu) m inan",
      "name": "head"
    }
  ],
  "lang": "Russian",
  "lang_code": "ru",
  "pos": "noun",
  "senses": [
    {
      "categories": [
        "Pages with 1 entry",
        "Pages with entries",
        "Russian 2-syllable words",
        "Russian entries with incorrect language header",
        "Russian non-lemma forms",
        "Russian noun forms",
        "Russian terms with IPA pronunciation"
      ],
      "form_of": [
        {
          "extra": "sbrod",
          "word": "сброд"
        }
      ],
      "glosses": [
        "dative singular of сброд (sbrod)"
      ],
      "links": [
        [
          "сброд",
          "сброд#Russian"
        ]
      ],
      "tags": [
        "dative",
        "form-of",
        "singular"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "[ˈzbrodʊ]"
    }
  ],
  "word": "сброду"
}

Download raw JSONL data for сброду meaning in Russian (0.8kB)


This page is a part of the kaikki.org machine-readable Russian dictionary. This dictionary is based on structured data extracted on 2024-12-21 from the enwiktionary dump dated 2024-12-04 using wiktextract (d8cb2f3 and 4e554ae). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.