"Хьюбертов" meaning in Russian

See Хьюбертов in All languages combined, or Wiktionary

Proper name

IPA: [ˈxʲjʉbʲɪrtəf] Forms: Хью́бертов [canonical], Xʹjúbertov [romanization]
Head templates: {{head|ru|proper noun form|head=Хью́бертов}} Хью́бертов • (Xʹjúbertov)
  1. genitive/accusative plural of Хью́берт (Xʹjúbert) Tags: accusative, form-of, genitive, plural Form of: Хью́берт (extra: Xʹjúbert)
    Sense id: en-Хьюбертов-ru-name-ZYvpw9uG Categories (other): Pages with 1 entry, Russian entries with incorrect language header
{
  "forms": [
    {
      "form": "Хью́бертов",
      "tags": [
        "canonical"
      ]
    },
    {
      "form": "Xʹjúbertov",
      "tags": [
        "romanization"
      ]
    }
  ],
  "head_templates": [
    {
      "args": {
        "1": "ru",
        "2": "proper noun form",
        "head": "Хью́бертов"
      },
      "expansion": "Хью́бертов • (Xʹjúbertov)",
      "name": "head"
    }
  ],
  "lang": "Russian",
  "lang_code": "ru",
  "pos": "name",
  "senses": [
    {
      "categories": [
        {
          "kind": "other",
          "name": "Pages with 1 entry",
          "parents": [],
          "source": "w"
        },
        {
          "kind": "other",
          "name": "Russian entries with incorrect language header",
          "parents": [
            "Entries with incorrect language header",
            "Entry maintenance"
          ],
          "source": "w"
        }
      ],
      "form_of": [
        {
          "extra": "Xʹjúbert",
          "word": "Хью́берт"
        }
      ],
      "glosses": [
        "genitive/accusative plural of Хью́берт (Xʹjúbert)"
      ],
      "id": "en-Хьюбертов-ru-name-ZYvpw9uG",
      "links": [
        [
          "Хью́берт",
          "Хьюберт#Russian"
        ]
      ],
      "tags": [
        "accusative",
        "form-of",
        "genitive",
        "plural"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "[ˈxʲjʉbʲɪrtəf]"
    }
  ],
  "word": "Хьюбертов"
}
{
  "forms": [
    {
      "form": "Хью́бертов",
      "tags": [
        "canonical"
      ]
    },
    {
      "form": "Xʹjúbertov",
      "tags": [
        "romanization"
      ]
    }
  ],
  "head_templates": [
    {
      "args": {
        "1": "ru",
        "2": "proper noun form",
        "head": "Хью́бертов"
      },
      "expansion": "Хью́бертов • (Xʹjúbertov)",
      "name": "head"
    }
  ],
  "lang": "Russian",
  "lang_code": "ru",
  "pos": "name",
  "senses": [
    {
      "categories": [
        "Pages with 1 entry",
        "Russian 3-syllable words",
        "Russian entries with incorrect language header",
        "Russian non-lemma forms",
        "Russian proper noun forms",
        "Russian terms with IPA pronunciation"
      ],
      "form_of": [
        {
          "extra": "Xʹjúbert",
          "word": "Хью́берт"
        }
      ],
      "glosses": [
        "genitive/accusative plural of Хью́берт (Xʹjúbert)"
      ],
      "links": [
        [
          "Хью́берт",
          "Хьюберт#Russian"
        ]
      ],
      "tags": [
        "accusative",
        "form-of",
        "genitive",
        "plural"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "[ˈxʲjʉbʲɪrtəf]"
    }
  ],
  "word": "Хьюбертов"
}

Download raw JSONL data for Хьюбертов meaning in Russian (0.9kB)


This page is a part of the kaikki.org machine-readable Russian dictionary. This dictionary is based on structured data extracted on 2024-09-22 from the enwiktionary dump dated 2024-09-20 using wiktextract (af5c55c and 66545a6). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.