"Хаммаршельд" meaning in Russian

{
  "etymology_templates": [
    {
      "args": {
        "1": "ru",
        "2": "sv",
        "3": "Hammarskjöld"
      },
      "expansion": "Swedish Hammarskjöld",
      "name": "bor"
    }
  ],
  "etymology_text": "From Swedish Hammarskjöld.",
  "forms": [
    {
      "form": "Хаммарше́льд",
      "tags": [
        "canonical"
      ]
    },
    {
      "form": "Xammaršélʹd",
      "tags": [
        "romanization"
      ]
    },
    {
      "form": "Хаммарше́льда",
      "tags": [
        "genitive"
      ]
    },
    {
      "form": "no-table-tags",
      "source": "declension",
      "tags": [
        "table-tags"
      ]
    },
    {
      "form": "ru-noun-table",
      "source": "declension",
      "tags": [
        "inflection-template"
      ]
    },
    {
      "form": "hard-stem",
      "source": "declension",
      "tags": [
        "class"
      ]
    },
    {
      "form": "accent-a",
      "source": "declension",
      "tags": [
        "class"
      ]
    },
    {
      "form": "Хаммарше́льд",
      "roman": "Xammaršélʹd",
      "source": "declension",
      "tags": [
        "nominative",
        "singular"
      ]
    },
    {
      "form": "Хаммарше́льды",
      "roman": "Xammaršélʹdy",
      "source": "declension",
      "tags": [
        "nominative",
        "plural"
      ]
    },
    {
      "form": "Хаммарше́льда",
      "roman": "Xammaršélʹda",
      "source": "declension",
      "tags": [
        "genitive",
        "singular"
      ]
    },
    {
      "form": "Хаммарше́льдов",
      "roman": "Xammaršélʹdov",
      "source": "declension",
      "tags": [
        "genitive",
        "plural"
      ]
    },
    {
      "form": "Хаммарше́льду",
      "roman": "Xammaršélʹdu",
      "source": "declension",
      "tags": [
        "dative",
        "singular"
      ]
    },
    {
      "form": "Хаммарше́льдам",
      "roman": "Xammaršélʹdam",
      "source": "declension",
      "tags": [
        "dative",
        "plural"
      ]
    },
    {
      "form": "Хаммарше́льд",
      "roman": "Xammaršélʹd",
      "source": "declension",
      "tags": [
        "accusative",
        "singular"
      ]
    },
    {
      "form": "Хаммарше́льды",
      "roman": "Xammaršélʹdy",
      "source": "declension",
      "tags": [
        "accusative",
        "plural"
      ]
    },
    {
      "form": "Хаммарше́льдом",
      "roman": "Xammaršélʹdom",
      "source": "declension",
      "tags": [
        "instrumental",
        "singular"
      ]
    },
    {
      "form": "Хаммарше́льдами",
      "roman": "Xammaršélʹdami",
      "source": "declension",
      "tags": [
        "instrumental",
        "plural"
      ]
    },
    {
      "form": "Хаммарше́льде",
      "roman": "Xammaršélʹde",
      "source": "declension",
      "tags": [
        "prepositional",
        "singular"
      ]
    },
    {
      "form": "Хаммарше́льдах",
      "roman": "Xammaršélʹdax",
      "source": "declension",
      "tags": [
        "plural",
        "prepositional"
      ]
    }
  ],
  "head_templates": [
    {
      "args": {
        "1": "Хаммарше́льд"
      },
      "expansion": "Хаммарше́льд • (Xammaršélʹd) m inan (genitive Хаммарше́льда)",
      "name": "ru-proper noun+"
    }
  ],
  "lang": "Russian",
  "lang_code": "ru",
  "pos": "name",
  "senses": [
    {
      "categories": [
        {
          "kind": "other",
          "name": "Russian entries with incorrect language header",
          "parents": [
            "Entries with incorrect language header",
            "Entry maintenance"
          ],
          "source": "w"
        },
        {
          "kind": "other",
          "name": "Russian links with redundant wikilinks",
          "parents": [
            "Links with redundant wikilinks",
            "Entry maintenance"
          ],
          "source": "w"
        },
        {
          "kind": "other",
          "name": "Russian nouns with accent pattern a",
          "parents": [],
          "source": "w"
        },
        {
          "kind": "other",
          "name": "Russian renderings of Swedish surnames",
          "parents": [],
          "source": "w"
        }
      ],
      "glosses": [
        "A transliteration of the Swedish surname Hammarskjöld"
      ],
      "id": "en-Хаммаршельд-ru-name-533B1IV9",
      "links": [
        [
          "Hammarskjöld",
          "Hammarskjöld#Swedish"
        ]
      ],
      "wikipedia": [
        "ru:Хаммаршельд"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "[xəmɐrˈʂɛlʲt]"
    }
  ],
  "word": "Хаммаршельд"
}

{
  "etymology_templates": [
    {
      "args": {
        "1": "ru",
        "2": "sv",
        "3": "Hammarskjöld"
      },
      "expansion": "Swedish Hammarskjöld",
      "name": "bor"
    }
  ],
  "etymology_text": "From Swedish Hammarskjöld.",
  "forms": [
    {
      "form": "Хаммарше́льд",
      "tags": [
        "canonical"
      ]
    },
    {
      "form": "Xammaršélʹd",
      "tags": [
        "romanization"
      ]
    },
    {
      "form": "Хаммарше́льда",
      "tags": [
        "genitive"
      ]
    },
    {
      "form": "no-table-tags",
      "source": "declension",
      "tags": [
        "table-tags"
      ]
    },
    {
      "form": "ru-noun-table",
      "source": "declension",
      "tags": [
        "inflection-template"
      ]
    },
    {
      "form": "hard-stem",
      "source": "declension",
      "tags": [
        "class"
      ]
    },
    {
      "form": "accent-a",
      "source": "declension",
      "tags": [
        "class"
      ]
    },
    {
      "form": "Хаммарше́льд",
      "roman": "Xammaršélʹd",
      "source": "declension",
      "tags": [
        "nominative",
        "singular"
      ]
    },
    {
      "form": "Хаммарше́льды",
      "roman": "Xammaršélʹdy",
      "source": "declension",
      "tags": [
        "nominative",
        "plural"
      ]
    },
    {
      "form": "Хаммарше́льда",
      "roman": "Xammaršélʹda",
      "source": "declension",
      "tags": [
        "genitive",
        "singular"
      ]
    },
    {
      "form": "Хаммарше́льдов",
      "roman": "Xammaršélʹdov",
      "source": "declension",
      "tags": [
        "genitive",
        "plural"
      ]
    },
    {
      "form": "Хаммарше́льду",
      "roman": "Xammaršélʹdu",
      "source": "declension",
      "tags": [
        "dative",
        "singular"
      ]
    },
    {
      "form": "Хаммарше́льдам",
      "roman": "Xammaršélʹdam",
      "source": "declension",
      "tags": [
        "dative",
        "plural"
      ]
    },
    {
      "form": "Хаммарше́льд",
      "roman": "Xammaršélʹd",
      "source": "declension",
      "tags": [
        "accusative",
        "singular"
      ]
    },
    {
      "form": "Хаммарше́льды",
      "roman": "Xammaršélʹdy",
      "source": "declension",
      "tags": [
        "accusative",
        "plural"
      ]
    },
    {
      "form": "Хаммарше́льдом",
      "roman": "Xammaršélʹdom",
      "source": "declension",
      "tags": [
        "instrumental",
        "singular"
      ]
    },
    {
      "form": "Хаммарше́льдами",
      "roman": "Xammaršélʹdami",
      "source": "declension",
      "tags": [
        "instrumental",
        "plural"
      ]
    },
    {
      "form": "Хаммарше́льде",
      "roman": "Xammaršélʹde",
      "source": "declension",
      "tags": [
        "prepositional",
        "singular"
      ]
    },
    {
      "form": "Хаммарше́льдах",
      "roman": "Xammaršélʹdax",
      "source": "declension",
      "tags": [
        "plural",
        "prepositional"
      ]
    }
  ],
  "head_templates": [
    {
      "args": {
        "1": "Хаммарше́льд"
      },
      "expansion": "Хаммарше́льд • (Xammaršélʹd) m inan (genitive Хаммарше́льда)",
      "name": "ru-proper noun+"
    }
  ],
  "lang": "Russian",
  "lang_code": "ru",
  "pos": "name",
  "senses": [
    {
      "categories": [
        "Russian 3-syllable words",
        "Russian entries with incorrect language header",
        "Russian hard-stem masculine-form accent-a nouns",
        "Russian hard-stem masculine-form nouns",
        "Russian inanimate nouns",
        "Russian lemmas",
        "Russian links with redundant wikilinks",
        "Russian masculine nouns",
        "Russian nouns with accent pattern a",
        "Russian proper nouns",
        "Russian renderings of Swedish surnames",
        "Russian terms borrowed from Swedish",
        "Russian terms derived from Swedish",
        "Russian terms with IPA pronunciation"
      ],
      "glosses": [
        "A transliteration of the Swedish surname Hammarskjöld"
      ],
      "links": [
        [
          "Hammarskjöld",
          "Hammarskjöld#Swedish"
        ]
      ],
      "wikipedia": [
        "ru:Хаммаршельд"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "[xəmɐrˈʂɛlʲt]"
    }
  ],
  "word": "Хаммаршельд"
}