See Berezovschi in All languages combined, or Wiktionary
Download JSON data for Berezovschi meaning in Romanian (1.7kB)
{
"etymology_templates": [
{
"args": {
"1": "ro",
"2": "uk",
"3": "Березовський"
},
"expansion": "Borrowed from Ukrainian Березовський (Berezovsʹkyj)",
"name": "bor+"
}
],
"etymology_text": "Borrowed from Ukrainian Березовський (Berezovsʹkyj).",
"forms": [
{
"form": "lui Berezovschi",
"tags": [
"dative",
"genitive"
]
}
],
"head_templates": [
{
"args": {
"1": "ro",
"10": "",
"11": "",
"12": "",
"13": "",
"14": "",
"2": "proper noun",
"3": "genitive/dative",
"4": "lui Berezovschi",
"5": "",
"6": "",
"7": "",
"8": "",
"9": "",
"g": "m",
"g2": "",
"head": "",
"sort": ""
},
"expansion": "Berezovschi m (genitive/dative lui Berezovschi)",
"name": "head"
},
{
"args": {
"1": "m"
},
"expansion": "Berezovschi m (genitive/dative lui Berezovschi)",
"name": "ro-name"
}
],
"lang": "Romanian",
"lang_code": "ro",
"pos": "name",
"senses": [
{
"categories": [
{
"kind": "other",
"name": "Romanian entries with incorrect language header",
"parents": [
"Entries with incorrect language header",
"Entry maintenance"
],
"source": "w"
},
{
"kind": "other",
"name": "Romanian surnames",
"parents": [],
"source": "w"
}
],
"glosses": [
"a surname from Ukrainian"
],
"id": "en-Berezovschi-ro-name-sBjsvmC-",
"links": [
[
"surname",
"surname"
]
],
"tags": [
"masculine"
]
}
],
"sounds": [
{
"audio": "LL-Q7913 (ron)-KlaudiuMihaila-Berezovschi.wav",
"mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/1/12/LL-Q7913_%28ron%29-KlaudiuMihaila-Berezovschi.wav/LL-Q7913_%28ron%29-KlaudiuMihaila-Berezovschi.wav.mp3",
"ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/1/12/LL-Q7913_%28ron%29-KlaudiuMihaila-Berezovschi.wav/LL-Q7913_%28ron%29-KlaudiuMihaila-Berezovschi.wav.ogg"
}
],
"word": "Berezovschi"
}
{
"etymology_templates": [
{
"args": {
"1": "ro",
"2": "uk",
"3": "Березовський"
},
"expansion": "Borrowed from Ukrainian Березовський (Berezovsʹkyj)",
"name": "bor+"
}
],
"etymology_text": "Borrowed from Ukrainian Березовський (Berezovsʹkyj).",
"forms": [
{
"form": "lui Berezovschi",
"tags": [
"dative",
"genitive"
]
}
],
"head_templates": [
{
"args": {
"1": "ro",
"10": "",
"11": "",
"12": "",
"13": "",
"14": "",
"2": "proper noun",
"3": "genitive/dative",
"4": "lui Berezovschi",
"5": "",
"6": "",
"7": "",
"8": "",
"9": "",
"g": "m",
"g2": "",
"head": "",
"sort": ""
},
"expansion": "Berezovschi m (genitive/dative lui Berezovschi)",
"name": "head"
},
{
"args": {
"1": "m"
},
"expansion": "Berezovschi m (genitive/dative lui Berezovschi)",
"name": "ro-name"
}
],
"lang": "Romanian",
"lang_code": "ro",
"pos": "name",
"senses": [
{
"categories": [
"Romanian entries with incorrect language header",
"Romanian lemmas",
"Romanian masculine nouns",
"Romanian proper nouns",
"Romanian surnames",
"Romanian surnames from Ukrainian",
"Romanian terms borrowed from Ukrainian",
"Romanian terms derived from Ukrainian",
"Romanian terms with audio links"
],
"glosses": [
"a surname from Ukrainian"
],
"links": [
[
"surname",
"surname"
]
],
"tags": [
"masculine"
]
}
],
"sounds": [
{
"audio": "LL-Q7913 (ron)-KlaudiuMihaila-Berezovschi.wav",
"mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/1/12/LL-Q7913_%28ron%29-KlaudiuMihaila-Berezovschi.wav/LL-Q7913_%28ron%29-KlaudiuMihaila-Berezovschi.wav.mp3",
"ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/1/12/LL-Q7913_%28ron%29-KlaudiuMihaila-Berezovschi.wav/LL-Q7913_%28ron%29-KlaudiuMihaila-Berezovschi.wav.ogg"
}
],
"word": "Berezovschi"
}
This page is a part of the kaikki.org machine-readable Romanian dictionary. This dictionary is based on structured data extracted on 2024-06-23 from the enwiktionary dump dated 2024-06-20 using wiktextract (1b9bfc5 and 0136956). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.
If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.