"ammazzasentenze" meaning in Italian

{
  "etymology_templates": [
    {
      "args": {
        "1": "ammazzare<t:to kill>",
        "2": "sentenza<t:verdicts><pl:1>"
      },
      "expansion": "Verb-object compound, composed of ammazza (“to kill”) + sentenze (“verdicts”)",
      "name": "it-verb-obj"
    }
  ],
  "etymology_text": "Verb-object compound, composed of ammazza (“to kill”) + sentenze (“verdicts”).",
  "head_templates": [
    {
      "args": {
        "inv": "1"
      },
      "expansion": "ammazzasentenze (invariable)",
      "name": "it-adj"
    }
  ],
  "hyphenation": [
    "am‧maz‧za‧sen‧tèn‧ze"
  ],
  "lang": "Italian",
  "lang_code": "it",
  "pos": "adj",
  "senses": [
    {
      "categories": [
        {
          "kind": "other",
          "name": "Italian entries with incorrect language header",
          "parents": [
            "Entries with incorrect language header",
            "Entry maintenance"
          ],
          "source": "w"
        },
        {
          "kind": "other",
          "name": "Italian links with redundant wikilinks",
          "parents": [
            "Links with redundant wikilinks",
            "Entry maintenance"
          ],
          "source": "w"
        },
        {
          "kind": "other",
          "name": "Italian verb-object compounds",
          "parents": [
            "Verb-object compounds",
            "Compound terms",
            "Terms by etymology"
          ],
          "source": "w"
        },
        {
          "kind": "topical",
          "langcode": "it",
          "name": "Law",
          "orig": "it:Law",
          "parents": [
            "Justice",
            "Society",
            "All topics",
            "Fundamental"
          ],
          "source": "w"
        }
      ],
      "glosses": [
        "describing a judge who has a reputation for finding notorious famous people not guilty"
      ],
      "id": "en-ammazzasentenze-it-adj-NCeEJ~2E",
      "links": [
        [
          "law",
          "law#English"
        ],
        [
          "judge",
          "judge"
        ],
        [
          "not guilty",
          "not guilty"
        ]
      ],
      "raw_glosses": [
        "(informal, law) describing a judge who has a reputation for finding notorious famous people not guilty"
      ],
      "tags": [
        "informal",
        "invariable"
      ],
      "topics": [
        "law"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "/amˌmat.t͡sa.senˈtɛn.t͡se/"
    },
    {
      "rhymes": "-ɛntse"
    }
  ],
  "word": "ammazzasentenze"
}

{
  "etymology_templates": [
    {
      "args": {
        "1": "ammazzare<t:to kill>",
        "2": "sentenza<t:verdicts><pl:1>"
      },
      "expansion": "Verb-object compound, composed of ammazza (“to kill”) + sentenze (“verdicts”)",
      "name": "it-verb-obj"
    }
  ],
  "etymology_text": "Verb-object compound, composed of ammazza (“to kill”) + sentenze (“verdicts”).",
  "head_templates": [
    {
      "args": {
        "inv": "1"
      },
      "expansion": "ammazzasentenze (invariable)",
      "name": "it-adj"
    }
  ],
  "hyphenation": [
    "am‧maz‧za‧sen‧tèn‧ze"
  ],
  "lang": "Italian",
  "lang_code": "it",
  "pos": "adj",
  "senses": [
    {
      "categories": [
        "Italian 6-syllable words",
        "Italian adjectives",
        "Italian entries with incorrect language header",
        "Italian indeclinable adjectives",
        "Italian informal terms",
        "Italian lemmas",
        "Italian links with redundant wikilinks",
        "Italian terms with IPA pronunciation",
        "Italian verb-object compounds",
        "Rhymes:Italian/ɛntse",
        "Rhymes:Italian/ɛntse/6 syllables",
        "it:Law"
      ],
      "glosses": [
        "describing a judge who has a reputation for finding notorious famous people not guilty"
      ],
      "links": [
        [
          "law",
          "law#English"
        ],
        [
          "judge",
          "judge"
        ],
        [
          "not guilty",
          "not guilty"
        ]
      ],
      "raw_glosses": [
        "(informal, law) describing a judge who has a reputation for finding notorious famous people not guilty"
      ],
      "tags": [
        "informal",
        "invariable"
      ],
      "topics": [
        "law"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "/amˌmat.t͡sa.senˈtɛn.t͡se/"
    },
    {
      "rhymes": "-ɛntse"
    }
  ],
  "word": "ammazzasentenze"
}