"zillionaire" meaning in English

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  "etymology_text": "From zillion + -aire.",
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      "form": "zillionaires",
      "tags": [
        "plural"
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      "expansion": "zillionaire (plural zillionaires)",
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  "lang_code": "en",
  "pos": "noun",
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        {
          "ref": "2021 December 13, Molly Ball, Jeffrey Kluger, Alejandro de la Garza, “Elon Musk: Person of the Year 2021”, in Time:",
          "text": "“Just dropping some friends off at the pool,” the 50-year-old zillionaire informed his 66 million Twitter followers on the evening of Nov. 29, having previously advised that at least half his tweets were “made on a porcelain throne.”",
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      "glosses": [
        "An incredibly rich person."
      ],
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          "humorous",
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        [
          "incredibly",
          "incredibly"
        ],
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          "rich",
          "rich"
        ]
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      "raw_glosses": [
        "(humorous, slang) An incredibly rich person."
      ],
      "synonyms": [
        {
          "word": "bajillionaire"
        },
        {
          "word": "bazillionaire"
        },
        {
          "word": "gazillionaire"
        },
        {
          "word": "squillionaire"
        }
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  "word": "zillionaire"
}

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      "expansion": "zillion + -aire",
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  ],
  "etymology_text": "From zillion + -aire.",
  "forms": [
    {
      "form": "zillionaires",
      "tags": [
        "plural"
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  "lang_code": "en",
  "pos": "noun",
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        {
          "ref": "2021 December 13, Molly Ball, Jeffrey Kluger, Alejandro de la Garza, “Elon Musk: Person of the Year 2021”, in Time:",
          "text": "“Just dropping some friends off at the pool,” the 50-year-old zillionaire informed his 66 million Twitter followers on the evening of Nov. 29, having previously advised that at least half his tweets were “made on a porcelain throne.”",
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        }
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        "An incredibly rich person."
      ],
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          "incredibly",
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      "raw_glosses": [
        "(humorous, slang) An incredibly rich person."
      ],
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        "humorous",
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  "synonyms": [
    {
      "word": "bajillionaire"
    },
    {
      "word": "bazillionaire"
    },
    {
      "word": "gazillionaire"
    },
    {
      "word": "squillionaire"
    }
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  "word": "zillionaire"
}