See Jung in All languages combined, or Wiktionary
Download JSON data for Jung meaning in English (2.7kB)
{ "coordinate_terms": [ { "_dis1": "47 53", "word": "Freud" } ], "derived": [ { "_dis1": "47 53", "word": "Jungian" } ], "etymology_number": 1, "etymology_templates": [ { "args": { "1": "loanword", "2": "Borrowed" }, "expansion": "Borrowed", "name": "glossary" }, { "args": { "1": "en", "2": "de", "3": "Jung", "4": "", "5": "", "g": "", "g2": "", "g3": "", "id": "", "lit": "", "nocat": "", "pos": "", "sc": "", "sort": "", "tr": "", "ts": "" }, "expansion": "German Jung", "name": "bor" }, { "args": { "1": "en", "2": "de", "3": "Jung" }, "expansion": "Borrowed from German Jung", "name": "bor+" }, { "args": { "1": "en", "2": "Young" }, "expansion": "Doublet of Young", "name": "doublet" } ], "etymology_text": "Borrowed from German Jung. Doublet of Young.", "head_templates": [ { "args": {}, "expansion": "Jung", "name": "en-proper-noun" } ], "lang": "English", "lang_code": "en", "pos": "name", "senses": [ { "categories": [ { "_dis": "47 53", "kind": "other", "name": "English entries with incorrect language header", "parents": [ "Entries with incorrect language header", "Entry maintenance" ], "source": "w+disamb" } ], "glosses": [ "Jung, a surname of German origin" ], "id": "en-Jung-en-name-7X27F-Xz", "links": [ [ "Jung", "#German" ] ] }, { "categories": [ { "_dis": "47 53", "kind": "other", "name": "English entries with incorrect language header", "parents": [ "Entries with incorrect language header", "Entry maintenance" ], "source": "w+disamb" }, { "_dis": "26 43 32", "kind": "topical", "langcode": "en", "name": "Individuals", "orig": "en:Individuals", "parents": [ "People", "Human", "All topics", "Fundamental" ], "source": "w+disamb" }, { "_dis": "26 62 13", "kind": "topical", "langcode": "en", "name": "Psychoanalysis", "orig": "en:Psychoanalysis", "parents": [ "Psychology", "Social sciences", "Sciences", "Society", "All topics", "Fundamental" ], "source": "w+disamb" } ], "glosses": [ "Carl Jung, Swiss psychiatrist and psychotherapist who founded analytical psychology." ], "id": "en-Jung-en-name-xg28zgI-" } ], "sounds": [ { "ipa": "/jʊŋ/" } ], "wikipedia": [ "Jung (disambiguation)" ], "word": "Jung" } { "etymology_number": 2, "etymology_templates": [ { "args": { "1": "en", "2": "ko", "3": "정" }, "expansion": "Transliteration of Korean 정 (jeong)", "name": "translit" } ], "etymology_text": "Transliteration of Korean 정 (jeong).", "head_templates": [ { "args": {}, "expansion": "Jung", "name": "en-proper noun" } ], "lang": "English", "lang_code": "en", "pos": "name", "senses": [ { "categories": [ { "kind": "other", "name": "English surnames", "parents": [], "source": "w" } ], "glosses": [ "A surname from Korean." ], "id": "en-Jung-en-name-qe3-kOiv", "links": [ [ "surname", "surname" ] ] } ], "sounds": [ { "ipa": "/d͡ʒʌŋ/" } ], "wikipedia": [ "Jung (disambiguation)" ], "word": "Jung" }
{ "categories": [ "English 1-syllable words", "English doublets", "English entries with incorrect language header", "English lemmas", "English proper nouns", "English terms borrowed from German", "English terms derived from German", "English terms derived from Korean", "English terms with IPA pronunciation", "English transliterations of Korean terms", "English uncountable nouns", "en:Individuals", "en:Psychoanalysis" ], "coordinate_terms": [ { "word": "Freud" } ], "derived": [ { "word": "Jungian" } ], "etymology_number": 1, "etymology_templates": [ { "args": { "1": "loanword", "2": "Borrowed" }, "expansion": "Borrowed", "name": "glossary" }, { "args": { "1": "en", "2": "de", "3": "Jung", "4": "", "5": "", "g": "", "g2": "", "g3": "", "id": "", "lit": "", "nocat": "", "pos": "", "sc": "", "sort": "", "tr": "", "ts": "" }, "expansion": "German Jung", "name": "bor" }, { "args": { "1": "en", "2": "de", "3": "Jung" }, "expansion": "Borrowed from German Jung", "name": "bor+" }, { "args": { "1": "en", "2": "Young" }, "expansion": "Doublet of Young", "name": "doublet" } ], "etymology_text": "Borrowed from German Jung. Doublet of Young.", "head_templates": [ { "args": {}, "expansion": "Jung", "name": "en-proper-noun" } ], "lang": "English", "lang_code": "en", "pos": "name", "senses": [ { "glosses": [ "Jung, a surname of German origin" ], "links": [ [ "Jung", "#German" ] ] }, { "glosses": [ "Carl Jung, Swiss psychiatrist and psychotherapist who founded analytical psychology." ] } ], "sounds": [ { "ipa": "/jʊŋ/" } ], "wikipedia": [ "Jung (disambiguation)" ], "word": "Jung" } { "categories": [ "English 1-syllable words", "English lemmas", "English proper nouns", "English terms derived from Korean", "English terms with IPA pronunciation", "English transliterations of Korean terms", "English uncountable nouns", "en:Individuals", "en:Psychoanalysis" ], "etymology_number": 2, "etymology_templates": [ { "args": { "1": "en", "2": "ko", "3": "정" }, "expansion": "Transliteration of Korean 정 (jeong)", "name": "translit" } ], "etymology_text": "Transliteration of Korean 정 (jeong).", "head_templates": [ { "args": {}, "expansion": "Jung", "name": "en-proper noun" } ], "lang": "English", "lang_code": "en", "pos": "name", "senses": [ { "categories": [ "English surnames", "English surnames from Korean" ], "glosses": [ "A surname from Korean." ], "links": [ [ "surname", "surname" ] ] } ], "sounds": [ { "ipa": "/d͡ʒʌŋ/" } ], "wikipedia": [ "Jung (disambiguation)" ], "word": "Jung" }
This page is a part of the kaikki.org machine-readable English dictionary. This dictionary is based on structured data extracted on 2024-04-17 from the enwiktionary dump dated 2024-04-01 using wiktextract (0b52755 and 5cb0836). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.
If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.