"Aveyard" meaning in English

See Aveyard in All languages combined, or Wiktionary

Proper name

IPA: /ˈeːv.jaːd/
Etymology: Likely French. From Hayvyerd. Adopted as an alias by a man named Robert Janyn in Dewsbury, Yorkshire in the 16th century. Head templates: {{head|en|proper noun}} Aveyard
  1. An English surname.
    Sense id: en-Aveyard-en-name-2R-TG-Sa Categories (other): English entries with incorrect language header, English surnames, Pages with 1 entry, Pages with entries
     
{
  "etymology_text": "Likely French. From Hayvyerd. Adopted as an alias by a man named Robert Janyn in Dewsbury, Yorkshire in the 16th century.",
  "head_templates": [
    {
      "args": {
        "1": "en",
        "2": "proper noun"
      },
      "expansion": "Aveyard",
      "name": "head"
    }
  ],
  "lang": "English",
  "lang_code": "en",
  "pos": "name",
  "senses": [
    {
      "categories": [
        {
          "kind": "other",
          "name": "English entries with incorrect language header",
          "parents": [
            "Entries with incorrect language header",
            "Entry maintenance"
          ],
          "source": "w"
        },
        {
          "kind": "other",
          "name": "English surnames",
          "parents": [],
          "source": "w"
        },
        {
          "kind": "other",
          "name": "Pages with 1 entry",
          "parents": [],
          "source": "w"
        },
        {
          "kind": "other",
          "name": "Pages with entries",
          "parents": [],
          "source": "w"
        }
      ],
      "glosses": [
        "An English surname."
      ],
      "id": "en-Aveyard-en-name-2R-TG-Sa",
      "links": [
        [
          "English",
          "English"
        ],
        [
          "surname",
          "surname"
        ]
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "/ˈeːv.jaːd/"
    }
  ],
  "word": "Aveyard"
}

{
  "etymology_text": "Likely French. From Hayvyerd. Adopted as an alias by a man named Robert Janyn in Dewsbury, Yorkshire in the 16th century.",
  "head_templates": [
    {
      "args": {
        "1": "en",
        "2": "proper noun"
      },
      "expansion": "Aveyard",
      "name": "head"
    }
  ],
  "lang": "English",
  "lang_code": "en",
  "pos": "name",
  "senses": [
    {
      "categories": [
        "English entries with incorrect language header",
        "English lemmas",
        "English proper nouns",
        "English surnames",
        "Pages with 1 entry",
        "Pages with entries"
      ],
      "glosses": [
        "An English surname."
      ],
      "links": [
        [
          "English",
          "English"
        ],
        [
          "surname",
          "surname"
        ]
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "/ˈeːv.jaːd/"
    }
  ],
  "word": "Aveyard"
}

Download raw JSONL data for Aveyard meaning in English (0.6kB)

This page is a part of the kaikki.org machine-readable English dictionary. This dictionary is based on structured data extracted on 2025-01-18 from the enwiktionary dump dated 2025-01-01 using wiktextract (e4a2c88 and 4230888). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.