See spaideil on Wiktionary
{ "derived": [ { "_dis1": "0 0", "word": "cho spaideil ri seilcheag" } ], "etymology_templates": [ { "args": { "1": "gd", "2": "non", "3": "spázera", "4": "", "5": "to stroll" }, "expansion": "Old Norse spázera (“to stroll”)", "name": "der" }, { "args": { "1": "gd", "2": "gmh", "3": "spazieren" }, "expansion": "Middle High German spazieren", "name": "der" }, { "args": { "1": "gd", "2": "it", "3": "spaziare" }, "expansion": "Italian spaziare", "name": "der" }, { "args": { "1": "gd", "2": "la", "3": "spatiāri" }, "expansion": "Latin spatiāri", "name": "der" }, { "args": { "1": "gd", "2": "la", "3": "spatior", "4": "", "5": "to go for a walk" }, "expansion": "Latin spatior (“to go for a walk”)", "name": "der" }, { "args": { "1": "gd", "2": "non", "3": "spjátra", "t": "to act foppish" }, "expansion": "Old Norse spjátra (“to act foppish”)", "name": "der" } ], "etymology_text": "Possibly from Old Norse spázera (“to stroll”), from Middle High German spazieren, from Italian spaziare, from Latin spatiāri, present active infinitive of Latin spatior (“to go for a walk”), similarly to spaidsear (“strolling; sauntering”). The shift in meaning would be figurative, as with the English strut.\nAlternatively, from Old Norse spjátra (“to act foppish”), similarly to spadair (“fop; braggart”).", "head_templates": [ { "args": { "1": "gd", "10": "", "11": "", "12": "", "13": "", "14": "", "15": "", "16": "", "17": "", "18": "", "19": "", "2": "adjective", "20": "", "3": "", "4": "", "5": "", "6": "", "7": "", "8": "", "9": "", "f1accel-form": "gen|s|m", "f2accel-form": "gen|s|f", "f3accel-form": "gen|s|f", "f4accel-form": "p", "f5accel-form": "comparative", "f6accel-form": "comparative", "f7accel-form": "comparative", "f8accel-form": "qualitative", "f9accel-form": "qualitative", "head": "" }, "expansion": "spaideil", "name": "head" }, { "args": {}, "expansion": "spaideil", "name": "gd-adj" } ], "lang": "Scottish Gaelic", "lang_code": "gd", "pos": "adj", "senses": [ { "categories": [ { "_dis": "100 0", "kind": "other", "name": "Pages with 1 entry", "parents": [], "source": "w+disamb" }, { "_dis": "100 0", "kind": "other", "name": "Pages with entries", "parents": [], "source": "w+disamb" }, { "_dis": "95 5", "kind": "other", "name": "Scottish Gaelic entries with incorrect language header", "parents": [ "Entries with incorrect language header", "Entry maintenance" ], "source": "w+disamb" } ], "glosses": [ "well-dressed" ], "id": "en-spaideil-gd-adj-K2~gWtmA", "links": [ [ "well-dressed", "well-dressed" ] ] }, { "glosses": [ "dressy, fancy" ], "id": "en-spaideil-gd-adj-93jIDQYw", "links": [ [ "dressy", "dressy" ], [ "fancy", "fancy" ] ] } ], "sounds": [ { "ipa": "/ˈsbadʲal/" } ], "word": "spaideil" }
{ "categories": [ "Pages with 1 entry", "Pages with entries", "Scottish Gaelic adjectives", "Scottish Gaelic entries with incorrect language header", "Scottish Gaelic lemmas", "Scottish Gaelic terms derived from Italian", "Scottish Gaelic terms derived from Latin", "Scottish Gaelic terms derived from Middle High German", "Scottish Gaelic terms derived from Old Norse" ], "derived": [ { "word": "cho spaideil ri seilcheag" } ], "etymology_templates": [ { "args": { "1": "gd", "2": "non", "3": "spázera", "4": "", "5": "to stroll" }, "expansion": "Old Norse spázera (“to stroll”)", "name": "der" }, { "args": { "1": "gd", "2": "gmh", "3": "spazieren" }, "expansion": "Middle High German spazieren", "name": "der" }, { "args": { "1": "gd", "2": "it", "3": "spaziare" }, "expansion": "Italian spaziare", "name": "der" }, { "args": { "1": "gd", "2": "la", "3": "spatiāri" }, "expansion": "Latin spatiāri", "name": "der" }, { "args": { "1": "gd", "2": "la", "3": "spatior", "4": "", "5": "to go for a walk" }, "expansion": "Latin spatior (“to go for a walk”)", "name": "der" }, { "args": { "1": "gd", "2": "non", "3": "spjátra", "t": "to act foppish" }, "expansion": "Old Norse spjátra (“to act foppish”)", "name": "der" } ], "etymology_text": "Possibly from Old Norse spázera (“to stroll”), from Middle High German spazieren, from Italian spaziare, from Latin spatiāri, present active infinitive of Latin spatior (“to go for a walk”), similarly to spaidsear (“strolling; sauntering”). The shift in meaning would be figurative, as with the English strut.\nAlternatively, from Old Norse spjátra (“to act foppish”), similarly to spadair (“fop; braggart”).", "head_templates": [ { "args": { "1": "gd", "10": "", "11": "", "12": "", "13": "", "14": "", "15": "", "16": "", "17": "", "18": "", "19": "", "2": "adjective", "20": "", "3": "", "4": "", "5": "", "6": "", "7": "", "8": "", "9": "", "f1accel-form": "gen|s|m", "f2accel-form": "gen|s|f", "f3accel-form": "gen|s|f", "f4accel-form": "p", "f5accel-form": "comparative", "f6accel-form": "comparative", "f7accel-form": "comparative", "f8accel-form": "qualitative", "f9accel-form": "qualitative", "head": "" }, "expansion": "spaideil", "name": "head" }, { "args": {}, "expansion": "spaideil", "name": "gd-adj" } ], "lang": "Scottish Gaelic", "lang_code": "gd", "pos": "adj", "senses": [ { "glosses": [ "well-dressed" ], "links": [ [ "well-dressed", "well-dressed" ] ] }, { "glosses": [ "dressy, fancy" ], "links": [ [ "dressy", "dressy" ], [ "fancy", "fancy" ] ] } ], "sounds": [ { "ipa": "/ˈsbadʲal/" } ], "word": "spaideil" }
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This page is a part of the kaikki.org machine-readable All languages combined dictionary. This dictionary is based on structured data extracted on 2024-12-01 from the enwiktionary dump dated 2024-11-21 using wiktextract (95d2be1 and 64224ec). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.
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