"self-commutator" meaning in All languages combined

{
  "etymology_templates": [
    {
      "args": {
        "1": "en",
        "2": "self",
        "3": "commutator"
      },
      "expansion": "self- + commutator",
      "name": "prefix"
    }
  ],
  "etymology_text": "From self- + commutator.",
  "forms": [
    {
      "form": "self-commutators",
      "tags": [
        "plural"
      ]
    }
  ],
  "head_templates": [
    {
      "args": {},
      "expansion": "self-commutator (plural self-commutators)",
      "name": "en-noun"
    }
  ],
  "lang": "English",
  "lang_code": "en",
  "pos": "noun",
  "senses": [
    {
      "categories": [
        {
          "kind": "other",
          "name": "English entries with incorrect language header",
          "parents": [
            "Entries with incorrect language header",
            "Entry maintenance"
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          "source": "w"
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          "source": "w"
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        {
          "kind": "topical",
          "langcode": "en",
          "name": "Mathematics",
          "orig": "en:Mathematics",
          "parents": [
            "Formal sciences",
            "Sciences",
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            "Fundamental"
          ],
          "source": "w"
        }
      ],
      "glosses": [
        "Given a bounded linear operator B and its adjoint B*, the self-commutator is B*B - BB*."
      ],
      "id": "en-self-commutator-en-noun-0zv1ex4Z",
      "links": [
        [
          "mathematics",
          "mathematics"
        ],
        [
          "bounded",
          "bounded"
        ],
        [
          "linear",
          "linear"
        ],
        [
          "operator",
          "operator"
        ],
        [
          "adjoint",
          "adjoint"
        ]
      ],
      "raw_glosses": [
        "(mathematics) Given a bounded linear operator B and its adjoint B*, the self-commutator is B*B - BB*."
      ],
      "topics": [
        "mathematics",
        "sciences"
      ]
    }
  ],
  "word": "self-commutator"
}

{
  "etymology_templates": [
    {
      "args": {
        "1": "en",
        "2": "self",
        "3": "commutator"
      },
      "expansion": "self- + commutator",
      "name": "prefix"
    }
  ],
  "etymology_text": "From self- + commutator.",
  "forms": [
    {
      "form": "self-commutators",
      "tags": [
        "plural"
      ]
    }
  ],
  "head_templates": [
    {
      "args": {},
      "expansion": "self-commutator (plural self-commutators)",
      "name": "en-noun"
    }
  ],
  "lang": "English",
  "lang_code": "en",
  "pos": "noun",
  "senses": [
    {
      "categories": [
        "English countable nouns",
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        "English nouns",
        "English terms prefixed with self-",
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        "en:Mathematics"
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      "glosses": [
        "Given a bounded linear operator B and its adjoint B*, the self-commutator is B*B - BB*."
      ],
      "links": [
        [
          "mathematics",
          "mathematics"
        ],
        [
          "bounded",
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        ],
        [
          "linear",
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        ],
        [
          "operator",
          "operator"
        ],
        [
          "adjoint",
          "adjoint"
        ]
      ],
      "raw_glosses": [
        "(mathematics) Given a bounded linear operator B and its adjoint B*, the self-commutator is B*B - BB*."
      ],
      "topics": [
        "mathematics",
        "sciences"
      ]
    }
  ],
  "word": "self-commutator"
}