"lord of gingerbread" meaning in All languages combined

See lord of gingerbread on Wiktionary

Noun [English]

Head templates: {{en-noun|?}} lord of gingerbread
  1. (idiomatic, obsolete) One who is showy but lacking substance or real authority. Tags: idiomatic, obsolete Synonyms: man of gingerbread
    Sense id: en-lord_of_gingerbread-en-noun-~~l5DdLX Categories (other): English entries with incorrect language header, Pages with 1 entry, Pages with entries
{
  "head_templates": [
    {
      "args": {
        "1": "?"
      },
      "expansion": "lord of gingerbread",
      "name": "en-noun"
    }
  ],
  "lang": "English",
  "lang_code": "en",
  "pos": "noun",
  "senses": [
    {
      "categories": [
        {
          "kind": "other",
          "name": "English entries with incorrect language header",
          "parents": [],
          "source": "w"
        },
        {
          "kind": "other",
          "name": "Pages with 1 entry",
          "parents": [],
          "source": "w"
        },
        {
          "kind": "other",
          "name": "Pages with entries",
          "parents": [],
          "source": "w"
        }
      ],
      "glosses": [
        "One who is showy but lacking substance or real authority."
      ],
      "id": "en-lord_of_gingerbread-en-noun-~~l5DdLX",
      "links": [
        [
          "showy",
          "showy"
        ],
        [
          "substance",
          "substance"
        ],
        [
          "real",
          "real"
        ],
        [
          "authority",
          "authority"
        ]
      ],
      "raw_glosses": [
        "(idiomatic, obsolete) One who is showy but lacking substance or real authority."
      ],
      "synonyms": [
        {
          "word": "man of gingerbread"
        }
      ],
      "tags": [
        "idiomatic",
        "obsolete"
      ]
    }
  ],
  "word": "lord of gingerbread"
}
{
  "head_templates": [
    {
      "args": {
        "1": "?"
      },
      "expansion": "lord of gingerbread",
      "name": "en-noun"
    }
  ],
  "lang": "English",
  "lang_code": "en",
  "pos": "noun",
  "senses": [
    {
      "categories": [
        "English countable nouns",
        "English entries with incorrect language header",
        "English idioms",
        "English lemmas",
        "English multiword terms",
        "English nouns",
        "English nouns with unknown or uncertain plurals",
        "English terms with obsolete senses",
        "Pages with 1 entry",
        "Pages with entries"
      ],
      "glosses": [
        "One who is showy but lacking substance or real authority."
      ],
      "links": [
        [
          "showy",
          "showy"
        ],
        [
          "substance",
          "substance"
        ],
        [
          "real",
          "real"
        ],
        [
          "authority",
          "authority"
        ]
      ],
      "raw_glosses": [
        "(idiomatic, obsolete) One who is showy but lacking substance or real authority."
      ],
      "synonyms": [
        {
          "word": "man of gingerbread"
        }
      ],
      "tags": [
        "idiomatic",
        "obsolete"
      ]
    }
  ],
  "word": "lord of gingerbread"
}

Download raw JSONL data for lord of gingerbread meaning in All languages combined (0.8kB)


This page is a part of the kaikki.org machine-readable All languages combined dictionary. This dictionary is based on structured data extracted on 2025-06-01 from the enwiktionary dump dated 2025-05-20 using wiktextract (3dadd05 and f1c2b61). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.