"Shawforth" meaning in All languages combined

{
  "etymology_templates": [
    {
      "args": {
        "1": "en",
        "2": "ang",
        "3": "-"
      },
      "expansion": "Old English",
      "name": "inh"
    },
    {
      "args": {
        "1": "ang",
        "2": "shaw",
        "3": "ford",
        "nocat": "1",
        "t1": "wood or grove",
        "t2": "ford"
      },
      "expansion": "shaw (“wood or grove”) + ford (“ford”)",
      "name": "compound"
    }
  ],
  "etymology_text": "From Old English shaw (“wood or grove”) + ford (“ford”).",
  "forms": [
    {
      "form": "Shawforths",
      "tags": [
        "plural"
      ]
    }
  ],
  "head_templates": [
    {
      "args": {
        "1": "~",
        "2": "s"
      },
      "expansion": "Shawforth (countable and uncountable, plural Shawforths)",
      "name": "en-proper noun"
    }
  ],
  "lang": "English",
  "lang_code": "en",
  "pos": "name",
  "senses": [
    {
      "categories": [
        {
          "kind": "place",
          "langcode": "en",
          "name": "Places in England",
          "orig": "en:Places in England",
          "parents": [
            "Places",
            "Names",
            "All topics",
            "Proper nouns",
            "Terms by semantic function",
            "Fundamental",
            "Nouns",
            "Lemmas"
          ],
          "source": "w"
        },
        {
          "kind": "place",
          "langcode": "en",
          "name": "Places in Lancashire, England",
          "orig": "en:Places in Lancashire, England",
          "parents": [
            "Places",
            "Names",
            "All topics",
            "Proper nouns",
            "Terms by semantic function",
            "Fundamental",
            "Nouns",
            "Lemmas"
          ],
          "source": "w"
        }
      ],
      "glosses": [
        "A village and ward in the Township of Whitworth in Rossendale borough, Lancashire, England (OS grid ref SD8818)."
      ],
      "id": "en-Shawforth-en-name-jtNs~ub1",
      "links": [
        [
          "Rossendale",
          "Rossendale#English"
        ],
        [
          "Lancashire",
          "Lancashire#English"
        ],
        [
          "England",
          "England#English"
        ],
        [
          "OS",
          "OS"
        ]
      ],
      "tags": [
        "countable",
        "uncountable"
      ]
    },
    {
      "categories": [
        {
          "kind": "other",
          "name": "English surnames",
          "parents": [],
          "source": "w"
        },
        {
          "_dis": "24 76",
          "kind": "other",
          "name": "English entries with incorrect language header",
          "parents": [
            "Entries with incorrect language header",
            "Entry maintenance"
          ],
          "source": "w+disamb"
        }
      ],
      "glosses": [
        "A habitational surname from Old English."
      ],
      "id": "en-Shawforth-en-name-zLJicHqr",
      "links": [
        [
          "habitational",
          "habitational"
        ],
        [
          "surname",
          "surname"
        ]
      ],
      "tags": [
        "countable",
        "uncountable"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "/ˈʃɔːfɜːrθ/"
    }
  ],
  "word": "Shawforth"
}

{
  "categories": [
    "English 2-syllable words",
    "English countable nouns",
    "English entries with incorrect language header",
    "English lemmas",
    "English proper nouns",
    "English terms derived from Old English",
    "English terms inherited from Old English",
    "English terms with IPA pronunciation",
    "English uncountable nouns"
  ],
  "etymology_templates": [
    {
      "args": {
        "1": "en",
        "2": "ang",
        "3": "-"
      },
      "expansion": "Old English",
      "name": "inh"
    },
    {
      "args": {
        "1": "ang",
        "2": "shaw",
        "3": "ford",
        "nocat": "1",
        "t1": "wood or grove",
        "t2": "ford"
      },
      "expansion": "shaw (“wood or grove”) + ford (“ford”)",
      "name": "compound"
    }
  ],
  "etymology_text": "From Old English shaw (“wood or grove”) + ford (“ford”).",
  "forms": [
    {
      "form": "Shawforths",
      "tags": [
        "plural"
      ]
    }
  ],
  "head_templates": [
    {
      "args": {
        "1": "~",
        "2": "s"
      },
      "expansion": "Shawforth (countable and uncountable, plural Shawforths)",
      "name": "en-proper noun"
    }
  ],
  "lang": "English",
  "lang_code": "en",
  "pos": "name",
  "senses": [
    {
      "categories": [
        "en:Places in England",
        "en:Places in Lancashire, England"
      ],
      "glosses": [
        "A village and ward in the Township of Whitworth in Rossendale borough, Lancashire, England (OS grid ref SD8818)."
      ],
      "links": [
        [
          "Rossendale",
          "Rossendale#English"
        ],
        [
          "Lancashire",
          "Lancashire#English"
        ],
        [
          "England",
          "England#English"
        ],
        [
          "OS",
          "OS"
        ]
      ],
      "tags": [
        "countable",
        "uncountable"
      ]
    },
    {
      "categories": [
        "English surnames",
        "English surnames from Old English"
      ],
      "glosses": [
        "A habitational surname from Old English."
      ],
      "links": [
        [
          "habitational",
          "habitational"
        ],
        [
          "surname",
          "surname"
        ]
      ],
      "tags": [
        "countable",
        "uncountable"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "/ˈʃɔːfɜːrθ/"
    }
  ],
  "word": "Shawforth"
}