See Ginosa on Wiktionary
Download JSON data for Ginosa meaning in All languages combined (1.9kB)
{
"etymology_templates": [
{
"args": {
"1": "it",
"2": "la",
"3": "Genusium"
},
"expansion": "Latin Genusium",
"name": "uder"
}
],
"etymology_text": "From Latin Genusium.",
"head_templates": [
{
"args": {
"1": "f"
},
"expansion": "Ginosa f",
"name": "it-proper noun"
}
],
"lang": "Italian",
"lang_code": "it",
"pos": "name",
"senses": [
{
"categories": [
{
"kind": "other",
"name": "Italian entries with incorrect language header",
"parents": [
"Entries with incorrect language header",
"Entry maintenance"
],
"source": "w"
},
{
"kind": "other",
"name": "Italian undefined derivations",
"parents": [
"Undefined derivations",
"Entry maintenance"
],
"source": "w"
},
{
"kind": "place",
"langcode": "it",
"name": "Places in Apulia",
"orig": "it:Places in Apulia",
"parents": [
"Places",
"Names",
"All topics",
"Proper nouns",
"Terms by semantic function",
"Fundamental",
"Nouns",
"Lemmas"
],
"source": "w"
},
{
"kind": "place",
"langcode": "it",
"name": "Places in Italy",
"orig": "it:Places in Italy",
"parents": [
"Places",
"Names",
"All topics",
"Proper nouns",
"Terms by semantic function",
"Fundamental",
"Nouns",
"Lemmas"
],
"source": "w"
},
{
"kind": "place",
"langcode": "it",
"name": "Towns in Apulia",
"orig": "it:Towns in Apulia",
"parents": [
"Towns",
"Places",
"Polities",
"Names",
"All topics",
"Proper nouns",
"Terms by semantic function",
"Fundamental",
"Nouns",
"Lemmas"
],
"source": "w"
},
{
"kind": "place",
"langcode": "it",
"name": "Towns in Italy",
"orig": "it:Towns in Italy",
"parents": [
"Towns",
"Places",
"Polities",
"Names",
"All topics",
"Proper nouns",
"Terms by semantic function",
"Fundamental",
"Nouns",
"Lemmas"
],
"source": "w"
}
],
"derived": [
{
"word": "ginosino"
}
],
"glosses": [
"A town in Taranto, Apulia, Italy"
],
"id": "en-Ginosa-it-name-UQUTlR0l",
"links": [
[
"Taranto",
"Taranto#English"
],
[
"Apulia",
"Apulia#English"
],
[
"Italy",
"Italy#English"
]
],
"tags": [
"feminine"
],
"wikipedia": [
"it:Ginosa"
]
}
],
"word": "Ginosa"
}
{
"derived": [
{
"word": "ginosino"
}
],
"etymology_templates": [
{
"args": {
"1": "it",
"2": "la",
"3": "Genusium"
},
"expansion": "Latin Genusium",
"name": "uder"
}
],
"etymology_text": "From Latin Genusium.",
"head_templates": [
{
"args": {
"1": "f"
},
"expansion": "Ginosa f",
"name": "it-proper noun"
}
],
"lang": "Italian",
"lang_code": "it",
"pos": "name",
"senses": [
{
"categories": [
"Italian entries with incorrect language header",
"Italian feminine nouns",
"Italian lemmas",
"Italian proper nouns",
"Italian terms derived from Latin",
"Italian undefined derivations",
"it:Places in Apulia",
"it:Places in Italy",
"it:Towns in Apulia",
"it:Towns in Italy"
],
"glosses": [
"A town in Taranto, Apulia, Italy"
],
"links": [
[
"Taranto",
"Taranto#English"
],
[
"Apulia",
"Apulia#English"
],
[
"Italy",
"Italy#English"
]
],
"tags": [
"feminine"
],
"wikipedia": [
"it:Ginosa"
]
}
],
"word": "Ginosa"
}
This page is a part of the kaikki.org machine-readable All languages combined dictionary. This dictionary is based on structured data extracted on 2024-06-01 from the enwiktionary dump dated 2024-05-02 using wiktextract (384852d and db5a844). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.
If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.