"Garbarino" meaning in All languages combined

See Garbarino on Wiktionary

Proper name [English]

Forms: Garbarinos [plural]
Etymology: Borrowed from Italian Garbarino. Etymology templates: {{bor+|en|it|Garbarino}} Borrowed from Italian Garbarino Head templates: {{en-prop|s}} Garbarino (plural Garbarinos)
  1. A surname from Italian.
    Sense id: en-Garbarino-en-name-rsy3jwmJ Categories (other): English entries with incorrect language header, English surnames, Pages with 2 entries, Pages with entries

Proper name [Italian]

Head templates: {{it-proper noun|mfbysense}} Garbarino m or f by sense
  1. a surname Tags: by-personal-gender, feminine, masculine

Inflected forms

{
  "etymology_templates": [
    {
      "args": {
        "1": "en",
        "2": "it",
        "3": "Garbarino"
      },
      "expansion": "Borrowed from Italian Garbarino",
      "name": "bor+"
    }
  ],
  "etymology_text": "Borrowed from Italian Garbarino.",
  "forms": [
    {
      "form": "Garbarinos",
      "tags": [
        "plural"
      ]
    }
  ],
  "head_templates": [
    {
      "args": {
        "1": "s"
      },
      "expansion": "Garbarino (plural Garbarinos)",
      "name": "en-prop"
    }
  ],
  "lang": "English",
  "lang_code": "en",
  "pos": "name",
  "senses": [
    {
      "categories": [
        {
          "kind": "other",
          "name": "English entries with incorrect language header",
          "parents": [],
          "source": "w"
        },
        {
          "kind": "other",
          "name": "English surnames",
          "parents": [],
          "source": "w"
        },
        {
          "kind": "other",
          "name": "Pages with 2 entries",
          "parents": [],
          "source": "w"
        },
        {
          "kind": "other",
          "name": "Pages with entries",
          "parents": [],
          "source": "w"
        }
      ],
      "examples": [
        {
          "bold_text_offsets": [
            [
              148,
              157
            ]
          ],
          "ref": "2023 June 21, Haley Talbot and Kristin Wilson, “House votes to censure Democratic congressman who led Trump investigations”, in CNN:",
          "text": "The vote was 213-209 along party lines. Republican members of the House Ethics Committee – Michael Guest of Mississippi, Dave Joyce of Ohio, Andrew Garbarino of New York, John Rutherford of Florida and Michelle Fischbach of Minnesota – voted present. GOP Rep. Ken Buck of Colorado also voted present but he is not on the Ethics Committee.",
          "type": "quote"
        }
      ],
      "glosses": [
        "A surname from Italian."
      ],
      "id": "en-Garbarino-en-name-rsy3jwmJ",
      "links": [
        [
          "surname",
          "surname"
        ]
      ]
    }
  ],
  "word": "Garbarino"
}

{
  "head_templates": [
    {
      "args": {
        "1": "mfbysense"
      },
      "expansion": "Garbarino m or f by sense",
      "name": "it-proper noun"
    }
  ],
  "lang": "Italian",
  "lang_code": "it",
  "pos": "name",
  "senses": [
    {
      "categories": [
        {
          "kind": "other",
          "name": "Italian entries with incorrect language header",
          "parents": [],
          "source": "w"
        },
        {
          "kind": "other",
          "name": "Italian masculine and feminine nouns by sense",
          "parents": [],
          "source": "w"
        },
        {
          "kind": "other",
          "name": "Italian proper nouns with irregular gender",
          "parents": [],
          "source": "w"
        },
        {
          "kind": "other",
          "name": "Italian surnames",
          "parents": [],
          "source": "w"
        },
        {
          "kind": "other",
          "name": "Pages with 2 entries",
          "parents": [],
          "source": "w"
        },
        {
          "kind": "other",
          "name": "Pages with entries",
          "parents": [],
          "source": "w"
        }
      ],
      "glosses": [
        "a surname"
      ],
      "id": "en-Garbarino-it-name-v2O7m9sM",
      "links": [
        [
          "surname",
          "surname"
        ]
      ],
      "tags": [
        "by-personal-gender",
        "feminine",
        "masculine"
      ]
    }
  ],
  "word": "Garbarino"
}
{
  "etymology_templates": [
    {
      "args": {
        "1": "en",
        "2": "it",
        "3": "Garbarino"
      },
      "expansion": "Borrowed from Italian Garbarino",
      "name": "bor+"
    }
  ],
  "etymology_text": "Borrowed from Italian Garbarino.",
  "forms": [
    {
      "form": "Garbarinos",
      "tags": [
        "plural"
      ]
    }
  ],
  "head_templates": [
    {
      "args": {
        "1": "s"
      },
      "expansion": "Garbarino (plural Garbarinos)",
      "name": "en-prop"
    }
  ],
  "lang": "English",
  "lang_code": "en",
  "pos": "name",
  "senses": [
    {
      "categories": [
        "English countable nouns",
        "English entries with incorrect language header",
        "English lemmas",
        "English proper nouns",
        "English surnames",
        "English surnames from Italian",
        "English terms borrowed from Italian",
        "English terms derived from Italian",
        "English terms with quotations",
        "Pages with 2 entries",
        "Pages with entries"
      ],
      "examples": [
        {
          "bold_text_offsets": [
            [
              148,
              157
            ]
          ],
          "ref": "2023 June 21, Haley Talbot and Kristin Wilson, “House votes to censure Democratic congressman who led Trump investigations”, in CNN:",
          "text": "The vote was 213-209 along party lines. Republican members of the House Ethics Committee – Michael Guest of Mississippi, Dave Joyce of Ohio, Andrew Garbarino of New York, John Rutherford of Florida and Michelle Fischbach of Minnesota – voted present. GOP Rep. Ken Buck of Colorado also voted present but he is not on the Ethics Committee.",
          "type": "quote"
        }
      ],
      "glosses": [
        "A surname from Italian."
      ],
      "links": [
        [
          "surname",
          "surname"
        ]
      ]
    }
  ],
  "word": "Garbarino"
}

{
  "head_templates": [
    {
      "args": {
        "1": "mfbysense"
      },
      "expansion": "Garbarino m or f by sense",
      "name": "it-proper noun"
    }
  ],
  "lang": "Italian",
  "lang_code": "it",
  "pos": "name",
  "senses": [
    {
      "categories": [
        "Italian entries with incorrect language header",
        "Italian feminine nouns",
        "Italian lemmas",
        "Italian masculine and feminine nouns by sense",
        "Italian masculine nouns",
        "Italian nouns with multiple genders",
        "Italian proper nouns",
        "Italian proper nouns with irregular gender",
        "Italian surnames",
        "Pages with 2 entries",
        "Pages with entries"
      ],
      "glosses": [
        "a surname"
      ],
      "links": [
        [
          "surname",
          "surname"
        ]
      ],
      "tags": [
        "by-personal-gender",
        "feminine",
        "masculine"
      ]
    }
  ],
  "word": "Garbarino"
}

Download raw JSONL data for Garbarino meaning in All languages combined (2.1kB)


This page is a part of the kaikki.org machine-readable All languages combined dictionary. This dictionary is based on structured data extracted on 2025-06-24 from the enwiktionary dump dated 2025-06-20 using wiktextract (074e7de and f1c2b61). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.