See Demetrio on Wiktionary
{
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"2": "la",
"3": "Demetrius"
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"expansion": "Borrowed from Latin Demetrius",
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},
{
"args": {
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},
"expansion": "Ancient Greek Δημήτριος (Dēmḗtrios)",
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{
"ipa": "/deˈmɛ.trjo/"
},
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],
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"sounds": [
{
"ipa": "/deˈmetɾjo/"
},
{
"ipa": "[d̪eˈme.t̪ɾjo]"
},
{
"rhymes": "-etɾjo"
}
],
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}
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],
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],
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"a male given name, equivalent to English Demetrius"
],
"links": [
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]
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],
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}
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"Spanish male given names",
"Spanish masculine nouns",
"Spanish proper nouns",
"Spanish terms borrowed from Latin",
"Spanish terms derived from Ancient Greek",
"Spanish terms derived from Latin",
"Spanish terms with IPA pronunciation"
],
"glosses": [
"a male given name, equivalent to English Demetrius"
],
"links": [
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],
[
"Demetrius",
"Demetrius#English"
]
],
"tags": [
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}
],
"sounds": [
{
"ipa": "/deˈmetɾjo/"
},
{
"ipa": "[d̪eˈme.t̪ɾjo]"
},
{
"rhymes": "-etɾjo"
}
],
"word": "Demetrio"
}
Download raw JSONL data for Demetrio meaning in All languages combined (2.8kB)
This page is a part of the kaikki.org machine-readable All languages combined dictionary. This dictionary is based on structured data extracted on 2025-05-19 from the enwiktionary dump dated 2025-05-01 using wiktextract (c3cc510 and 1d3fdbf). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.
If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.