"호주인" meaning in All languages combined

See 호주인 on Wiktionary

Noun [Korean]

IPA: [ɸʷo̞d͡ʑuin] [SK-Standard, Seoul] Forms: hoju'in [romanization], 濠洲人 [hanja]
Etymology: Sino-Korean word from 濠洲 (“Australia”) + 人 (“person”). Etymology templates: {{etymid|ko|濠洲人}}, {{ko-etym-sino|濠洲|Australia|人|person|suffix=y}} Sino-Korean word from 濠洲 (“Australia”) + 人 (“person”) Head templates: {{ko-noun|hanja=濠洲人}} 호주인 • (hoju'in) (hanja 濠洲人)
  1. Australian (person) Categories (topical): Nationalities Synonyms: 호주(濠洲) 사람, 오스트레일리아 사람, 오스트레일리아인
{
  "etymology_templates": [
    {
      "args": {
        "1": "ko",
        "2": "濠洲人"
      },
      "expansion": "",
      "name": "etymid"
    },
    {
      "args": {
        "1": "濠洲",
        "2": "Australia",
        "3": "人",
        "4": "person",
        "suffix": "y"
      },
      "expansion": "Sino-Korean word from 濠洲 (“Australia”) + 人 (“person”)",
      "name": "ko-etym-sino"
    }
  ],
  "etymology_text": "Sino-Korean word from 濠洲 (“Australia”) + 人 (“person”).",
  "forms": [
    {
      "form": "hoju'in",
      "tags": [
        "romanization"
      ]
    },
    {
      "form": "濠洲人",
      "tags": [
        "hanja"
      ]
    }
  ],
  "head_templates": [
    {
      "args": {
        "hanja": "濠洲人"
      },
      "expansion": "호주인 • (hoju'in) (hanja 濠洲人)",
      "name": "ko-noun"
    }
  ],
  "lang": "Korean",
  "lang_code": "ko",
  "pos": "noun",
  "senses": [
    {
      "categories": [
        {
          "kind": "other",
          "name": "Korean entries with incorrect language header",
          "parents": [
            "Entries with incorrect language header",
            "Entry maintenance"
          ],
          "source": "w"
        },
        {
          "kind": "other",
          "name": "Korean terms suffixed with -인 (人)",
          "parents": [],
          "source": "w"
        },
        {
          "kind": "other",
          "name": "Korean terms with redundant script codes",
          "parents": [
            "Terms with redundant script codes",
            "Entry maintenance"
          ],
          "source": "w"
        },
        {
          "kind": "other",
          "name": "Korean terms with redundant transliterations",
          "parents": [
            "Terms with redundant transliterations",
            "Entry maintenance"
          ],
          "source": "w"
        },
        {
          "kind": "other",
          "name": "Pages with 1 entry",
          "parents": [],
          "source": "w"
        },
        {
          "kind": "other",
          "name": "Pages with entries",
          "parents": [],
          "source": "w"
        },
        {
          "kind": "other",
          "name": "Sino-Korean words",
          "parents": [],
          "source": "w"
        },
        {
          "kind": "topical",
          "langcode": "ko",
          "name": "Nationalities",
          "orig": "ko:Nationalities",
          "parents": [
            "Demonyms",
            "People",
            "Names",
            "Human",
            "All topics",
            "Proper nouns",
            "Terms by semantic function",
            "Fundamental",
            "Nouns",
            "Lemmas"
          ],
          "source": "w"
        }
      ],
      "glosses": [
        "Australian (person)"
      ],
      "id": "en-호주인-ko-noun-oP-lOwsP",
      "links": [
        [
          "Australian",
          "Australian"
        ]
      ],
      "synonyms": [
        {
          "word": "호주(濠洲) 사람"
        },
        {
          "word": "오스트레일리아 사람"
        },
        {
          "word": "오스트레일리아인"
        }
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "[ɸʷo̞d͡ʑuin]",
      "tags": [
        "SK-Standard",
        "Seoul"
      ]
    },
    {
      "hangeul": "호주인"
    },
    {
      "other": "[호주인]"
    }
  ],
  "word": "호주인"
}
{
  "etymology_templates": [
    {
      "args": {
        "1": "ko",
        "2": "濠洲人"
      },
      "expansion": "",
      "name": "etymid"
    },
    {
      "args": {
        "1": "濠洲",
        "2": "Australia",
        "3": "人",
        "4": "person",
        "suffix": "y"
      },
      "expansion": "Sino-Korean word from 濠洲 (“Australia”) + 人 (“person”)",
      "name": "ko-etym-sino"
    }
  ],
  "etymology_text": "Sino-Korean word from 濠洲 (“Australia”) + 人 (“person”).",
  "forms": [
    {
      "form": "hoju'in",
      "tags": [
        "romanization"
      ]
    },
    {
      "form": "濠洲人",
      "tags": [
        "hanja"
      ]
    }
  ],
  "head_templates": [
    {
      "args": {
        "hanja": "濠洲人"
      },
      "expansion": "호주인 • (hoju'in) (hanja 濠洲人)",
      "name": "ko-noun"
    }
  ],
  "lang": "Korean",
  "lang_code": "ko",
  "pos": "noun",
  "senses": [
    {
      "categories": [
        "Korean entries with incorrect language header",
        "Korean lemmas",
        "Korean nouns",
        "Korean terms suffixed with -인 (人)",
        "Korean terms with IPA pronunciation",
        "Korean terms with redundant script codes",
        "Korean terms with redundant transliterations",
        "Pages with 1 entry",
        "Pages with entries",
        "Sino-Korean words",
        "ko:Nationalities"
      ],
      "glosses": [
        "Australian (person)"
      ],
      "links": [
        [
          "Australian",
          "Australian"
        ]
      ],
      "synonyms": [
        {
          "word": "호주(濠洲) 사람"
        },
        {
          "word": "오스트레일리아 사람"
        },
        {
          "word": "오스트레일리아인"
        }
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "[ɸʷo̞d͡ʑuin]",
      "tags": [
        "SK-Standard",
        "Seoul"
      ]
    },
    {
      "hangeul": "호주인"
    },
    {
      "other": "[호주인]"
    }
  ],
  "word": "호주인"
}

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This page is a part of the kaikki.org machine-readable All languages combined dictionary. This dictionary is based on structured data extracted on 2025-01-25 from the enwiktionary dump dated 2025-01-20 using wiktextract (c15a5ce and 5c11237). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.