"Шпанберга" meaning in All languages combined

{
  "etymology_templates": [
    {
      "args": {
        "1": "ru",
        "2": "Шпанберг",
        "3": "а"
      },
      "expansion": "Шпанберг (Španberg) + -а (-a)",
      "name": "suffix"
    }
  ],
  "etymology_text": "From Шпанберг (Španberg) + -а (-a), from Martin Spanberg, a Danish naval officer who served as one of Vitus Bering's lieutenants in the early Russian exploration of the Pacific Ocean. The suffix provides agreement with an implicit остров (ostrov, “island”).",
  "forms": [
    {
      "form": "Španberga",
      "tags": [
        "romanization"
      ]
    }
  ],
  "head_templates": [
    {
      "args": {
        "1": "ru",
        "2": "proper noun"
      },
      "expansion": "Шпанберга • (Španberga)",
      "name": "head"
    }
  ],
  "lang": "Russian",
  "lang_code": "ru",
  "pos": "name",
  "senses": [
    {
      "categories": [
        {
          "kind": "place",
          "langcode": "ru",
          "name": "Islands",
          "orig": "ru:Islands",
          "parents": [
            "Places",
            "Names",
            "All topics",
            "Proper nouns",
            "Terms by semantic function",
            "Fundamental",
            "Nouns",
            "Lemmas"
          ],
          "source": "w"
        },
        {
          "_dis": "74 26",
          "kind": "other",
          "name": "Pages with 1 entry",
          "parents": [],
          "source": "w+disamb"
        },
        {
          "_dis": "76 24",
          "kind": "other",
          "name": "Pages with entries",
          "parents": [],
          "source": "w+disamb"
        },
        {
          "_dis": "75 25",
          "kind": "other",
          "name": "Russian entries with incorrect language header",
          "parents": [
            "Entries with incorrect language header",
            "Entry maintenance"
          ],
          "source": "w+disamb"
        },
        {
          "_dis": "80 20",
          "kind": "other",
          "name": "Russian terms suffixed with -а",
          "parents": [],
          "source": "w+disamb"
        }
      ],
      "glosses": [
        "Shpanberg (an island in the Nordenskiöld Archipelago in the Kara Sea)"
      ],
      "id": "en-Шпанберга-ru-name-PA7QIqbW",
      "links": [
        [
          "Shpanberg",
          "Shpanberg#English"
        ],
        [
          "Nordenskiöld",
          "Nordenskiöld"
        ],
        [
          "Kara Sea",
          "Kara Sea"
        ]
      ]
    },
    {
      "categories": [],
      "glosses": [
        "Synonym of Шикотан (Šikotan), Shikotan, an island in the Kurils"
      ],
      "id": "en-Шпанберга-ru-name-8ZqKGgxx",
      "links": [
        [
          "Шикотан",
          "Шикотан#Russian"
        ],
        [
          "Shikotan",
          "Shikotan"
        ]
      ],
      "qualifier": "historical or disputed",
      "raw_glosses": [
        "(historical or disputed) Synonym of Шикотан (Šikotan), Shikotan, an island in the Kurils"
      ],
      "synonyms": [
        {
          "extra": "(Šikotan), Shikotan, an island in the Kurils",
          "tags": [
            "synonym",
            "synonym-of"
          ],
          "word": "Шикотан"
        }
      ]
    }
  ],
  "wikipedia": [
    "Martin Spanberg",
    "Vitus Bering"
  ],
  "word": "Шпанберга"
}

{
  "categories": [
    "Pages with 1 entry",
    "Pages with entries",
    "Russian entries with incorrect language header",
    "Russian eponyms",
    "Russian lemmas",
    "Russian proper nouns",
    "Russian terms borrowed from Danish",
    "Russian terms suffixed with -а"
  ],
  "etymology_templates": [
    {
      "args": {
        "1": "ru",
        "2": "Шпанберг",
        "3": "а"
      },
      "expansion": "Шпанберг (Španberg) + -а (-a)",
      "name": "suffix"
    }
  ],
  "etymology_text": "From Шпанберг (Španberg) + -а (-a), from Martin Spanberg, a Danish naval officer who served as one of Vitus Bering's lieutenants in the early Russian exploration of the Pacific Ocean. The suffix provides agreement with an implicit остров (ostrov, “island”).",
  "forms": [
    {
      "form": "Španberga",
      "tags": [
        "romanization"
      ]
    }
  ],
  "head_templates": [
    {
      "args": {
        "1": "ru",
        "2": "proper noun"
      },
      "expansion": "Шпанберга • (Španberga)",
      "name": "head"
    }
  ],
  "lang": "Russian",
  "lang_code": "ru",
  "pos": "name",
  "senses": [
    {
      "categories": [
        "ru:Islands"
      ],
      "glosses": [
        "Shpanberg (an island in the Nordenskiöld Archipelago in the Kara Sea)"
      ],
      "links": [
        [
          "Shpanberg",
          "Shpanberg#English"
        ],
        [
          "Nordenskiöld",
          "Nordenskiöld"
        ],
        [
          "Kara Sea",
          "Kara Sea"
        ]
      ]
    },
    {
      "categories": [
        "Russian terms with historical senses"
      ],
      "glosses": [
        "Synonym of Шикотан (Šikotan), Shikotan, an island in the Kurils"
      ],
      "links": [
        [
          "Шикотан",
          "Шикотан#Russian"
        ],
        [
          "Shikotan",
          "Shikotan"
        ]
      ],
      "qualifier": "historical or disputed",
      "raw_glosses": [
        "(historical or disputed) Synonym of Шикотан (Šikotan), Shikotan, an island in the Kurils"
      ],
      "synonyms": [
        {
          "extra": "(Šikotan), Shikotan, an island in the Kurils",
          "tags": [
            "synonym",
            "synonym-of"
          ],
          "word": "Шикотан"
        }
      ]
    }
  ],
  "wikipedia": [
    "Martin Spanberg",
    "Vitus Bering"
  ],
  "word": "Шпанберга"
}